在特定字词和/之后逐个删除字词 [英] Sed out word after specific word and /

问题描述

我正在使用grep在文本文件中搜索/Users/.这是输出:

I am using grep to search out /Users/ in a text file. This is the output:

'dir': u'/Users/dlee/Desktop',

有没有办法将Users/之后的单词读出来?也就是说，要获取dlee作为输出?

Is there a way to sed out the word after Users/? That is, to get dlee as the output?

推荐答案

使用grep和Perl正则表达式:

With grep and Perl regex:

$ grep -Po '(?<=/Users/)[^/]*' <<< "'dir': u'/Users/dlee/Desktop',"
dlee

• -o仅返回匹配项
• (?<=/Users/)是正向后看"，即比赛必须在比赛之后，但不包括在内
• [^/]*是除正斜杠之外的任意数量的字符
• -o returns only the match
• (?<=/Users/) is a "positive look-behind", i.e., the match has to be preceded by it but it is not included
• [^/]* is any number of characters except forward slashes

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