根节点中的Groovy XmlSlurper访问属性值 [英] Groovy XmlSlurper access attribute value in root node

问题描述

我正在尝试使用Groovy和XmlSlurper完成对属于根节点的属性的访问.我可以使用嵌套节点轻松地做到这一点，但似乎无法访问根节点.

I'm trying to accomplish accessing the attributes that are part of the root node using Groovy and XmlSlurper. I can do this easily with nested nodes, but can't seem to access the root node.

这是XML结构(简化):

Here is the XML structure (simplified):

<coverage lines-covered="2353" lines-valid="2943">
    <sources />
    <packages />
</coverage>

我希望能够获得行覆盖的和行有效的属性值.这是我正在尝试的代码:

I'd like to be able to get to the lines-covered and lines-valid attribute values. Here is the code I'm trying out:

def cobertura = new XmlSlurper().parse(xml)
def coverage = cobertura.coverage
def lines = cobertura.find { it.@lines-covered }
println lines

我也尝试过:

def cobertura = new XmlSlurper().parse("cobertura-coverage.xml")
def coverage = cobertura.coverage
println coverage.@lines-covered

并且:

def cobertura = new XmlSlurper().parse("cobertura-coverage.xml")
println cobertura.@lines-covered

推荐答案

您需要在lines-covered部分加引号，因为它包含破折号:

You need to put the lines-covered part in quotes since it contains a dash:

def cobertura = new XmlSlurper().parse("cobertura-coverage.xml")
println cobertura.@'lines-covered'

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