在Groovy中使用CollectEntries创建地图 [英] Create Map with CollectEntries in Groovy

问题描述

我有以下列表: appList = [DevOpsApplication，01.01.01]

I have the following list: appList = [DevOpsApplication, 01.01.01]

我想使用collectEntries创建地图.我知道it是指迭代的当前元素({ it -> it }的快捷方式).因此，我尝试使用索引:

I would like to create a map using collectEntries. I know that it refers to the current element of an iteration (shortcut for { it -> it }). Therefore, I tried to use the index:

def appMap = appList.collectEntries { [(it[0]):it[1]] }  

但是，这给了我

[D:e, 0:1]

但是我想要[DevOpsApplication: 01.01.01].有办法吗?

But I want [DevOpsApplication: 01.01.01]. Is there a way to do this?

此外，将来我希望将其扩展到2个以上的元素(例如[DevOpsApplication, 01.01.01, AnotherDevOpsApplication, 02.02.02])，并具有所需的[DevOpsApplication: 01.01.01, AnotherDevOpsApplication: 02.02.02]输出. 这怎么可能?

Additionally, In future I would like this to expand to more than 2 elements (e.g. [DevOpsApplication, 01.01.01, AnotherDevOpsApplication, 02.02.02]) with the desired output of [DevOpsApplication: 01.01.01, AnotherDevOpsApplication: 02.02.02]. How will this be possible?

推荐答案

我还找到了另一种方法. Groovy可以转换Object数组的值，并使用toSpreadMap()将它们转换为映射.但是，数组必须具有偶数个元素.

I also found another method. Groovy can convert the values of an Object array and convert them into a map with the toSpreadMap(). However, the array must have an even number of elements.

def appList = ['DevOpsApplication', '01.01.01']
def appMap = appList.toSpreadMap()

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