使用gson从序列化/反序列化中排除Kotlin数据类属性/字段 [英] Exclude a Kotlin data class property/field from serialization/deserialization using gson

问题描述

我正在尝试使用gson将Kotlin属性排除在反序列化之外.我尝试了不同的方法，从用@Transient注释属性到创建自定义注释策略(当然是在gson生成器中指定策略)，但是似乎没有任何作用，因为该属性不断获得null而不是我初始化的值财产.

I am trying to exclude a Kotlin property from deserialization using gson. I have tried different methods from annotating the property with @Transient to creating a custom annotation strategy (specifying the strategy in the gson builder of course), but nothing seems to be working, as the property keeps getting null instead of the value I initialized the property with.

我没有尝试使用@Expose注释，但是我不想使用@Expose

I have not tried using the @Expose annotation, but I do not want to annotate other fields with @Expose

请，我如何使用gson + Kotlin来实现这一目标?

Please, how can I achieve this please using gson + Kotlin?

推荐答案

@Transient为我工作.

@Transient worked for me.

@Transient lateinit var bar: SomeCustomType

每个@Transient定义:

Per @Transient definition:

将带注释的属性的JVM支持字段标记为transient， 表示它不是该对象的默认序列化形式的一部分.

Marks the JVM backing field of the annotated property as transient, meaning that it is not part of the default serialized form of the object.

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