删除字符串中空格后的所有内容 [英] Remove everything after space in string

问题描述

我想删除字符串中空格后的所有内容.

I would like to remove everything after a space in a string.

例如:

"my string is sad"

应该返回

"my"

我一直在尝试找出如何使用sub/gsub来执行此操作，但到目前为止仍未成功.

I've been trying to figure out how to do this using sub/gsub but have been unsuccessful so far.

推荐答案

strsplit("my string is sad"," ")[[1]][1]

这篇关于删除字符串中空格后的所有内容的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！