强制gsub保持尾随零 [英] Force gsub to keep trailing zeros

问题描述

我想提取."之后的数字.从data.frame [，1]中存储，并将它们存储在第二列中，如下所示:

I want to extract the digits after "." from data.frame[ ,1] and store them in a second column as following:

1 6.354 354 
2 6.355 355
3 6.363 363
4 6.367 367
5 6.378 378
6 6.419 419
7 6.426 426
8 6.427 427
9 6.428 428
10 6.431 431
11 6.460 46
12 6.477 477
(...)

为此，我使用gsub(".*\\.", "", data.frame[,1])，但这会忽略零，如您所见.在第11行中 如何提取."之后的完整数字/所有数字? 该列为数字.

To do that I use gsub(".*\\.", "", data.frame[,1]) but this ignores the zeros as you can see e.g. in row 11. How can I extract the complete number/all digits after the "."? The column is numeric.

推荐答案

如果为数字，则可能需要使用format或sprintf将其转换为character，然后使用sub

If this is numeric, then we may need to convert it to character using format or sprintf, and then use sub

sub("^[^.]*[.]", "", format(v1, width = max(nchar(v1))))
#[1] "354" "355" "460" "400" "012"

数据

v1 <- c(6.354, 6.355, 6.460, 6.400, 6.012)

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