Collections.reverse()vs Lists.reverse()哪一个更快? [英] Collections.reverse() vs Lists.reverse() which one is faster?

问题描述

我对以下问题感兴趣:Collections.reverse()vs Lists.reverse()哪个更快?

I am interested in following question: Collections.reverse() vs Lists.reverse() which one is faster?

谢谢.

推荐答案

他们做不同的事情.

Collections.reverse接受可变列表并颠倒其顺序.这需要线性时间.必须.

Collections.reverse takes a mutable list and reverses its order. It takes linear time. It has to.

番石榴的Lists.reverse返回反转列表的视图.它以固定的时间返回，但是您将为每个操作付出视图的(小)开销.

Guava's Lists.reverse returns a view of the list that is reversed. It returns in constant time, but you'll pay the (small) overhead of the view for each operation.

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