Python gzip:有没有办法从字符串解压缩? [英] Python gzip: is there a way to decompress from a string?
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问题描述
I am trying to decompress a .gz file coming from an URL.
url_file_handle=StringIO( gz_data )
gzip_file_handle=gzip.open(url_file_handle,"r")
decompressed_data = gzip_file_handle.read()
gzip_file_handle.close()
...但是我得到了 TypeError:强制转换为Unicode:需要字符串或缓冲区,cStringIO.StringI找到了
... but I get TypeError: coercing to Unicode: need string or buffer, cStringIO.StringI found
这是怎么回事?
Traceback (most recent call last):
File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2974, in _HandleRequest
base_env_dict=env_dict)
File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 411, in Dispatch
base_env_dict=base_env_dict)
File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2243, in Dispatch
self._module_dict)
File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2161, in ExecuteCGI
reset_modules = exec_script(handler_path, cgi_path, hook)
File "/opt/google/google_appengine-1.2.5/google/appengine/tools/dev_appserver.py", line 2057, in ExecuteOrImportScript
exec module_code in script_module.__dict__
File "/home/jldupont/workspace/jldupont/trunk/site/app/server/tasks/debian/repo_fetcher.py", line 36, in <module>
main()
File "/home/jldupont/workspace/jldupont/trunk/site/app/server/tasks/debian/repo_fetcher.py", line 30, in main
gziph=gzip.open(fh,'r')
File "/usr/lib/python2.5/gzip.py", line 49, in open
return GzipFile(filename, mode, compresslevel)
File "/usr/lib/python2.5/gzip.py", line 95, in __init__
fileobj = self.myfileobj = __builtin__.open(filename, mode or 'rb')
TypeError: coercing to Unicode: need string or buffer, cStringIO.StringI found
推荐答案
gzip.open
是打开文件的简写,您想要的是gzip.GzipFile
,您可以传递fileobj
gzip.open
is a shorthand for opening a file, what you want is gzip.GzipFile
which you can pass a fileobj
open(filename, mode='rb', compresslevel=9)
#Shorthand for GzipFile(filename, mode, compresslevel).
vs
class GzipFile
__init__(self, filename=None, mode=None, compresslevel=9, fileobj=None)
# At least one of fileobj and filename must be given a non-trivial value.
所以这应该对您有用
gzip_file_handle = gzip.GzipFile(fileobj=url_file_handle)
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