在Haskell中，floor和truncate之间有区别吗 [英] Is there a difference between floor and truncate in Haskell

问题描述

Haskell中的floor和truncate在功能上是否存在差异?

Does there exist a difference in functionality between floor and truncate in Haskell?

它们似乎执行相同的功能，并且具有相同的类型签名:

They seem to perform the same functionality and they have the same type signature:

• truncate :: (Integral b, RealFrac a) => a -> b
• floor :: (Integral b, RealFrac a) => a -> b

• truncate :: (Integral b, RealFrac a) => a -> b
• floor :: (Integral b, RealFrac a) => a -> b

推荐答案

是的，用于负数.如果阅读文档，将会看到:

Yes, for negative numbers. If we read the documentation, we see:

truncate :: Integral b => a -> b

truncate :: Integral b => a -> b

truncate x返回零和x之间最接近x的整数

truncate x returns the integer nearest x between zero and x

和:

floor :: Integral b => a -> b

floor :: Integral b => a -> b

floor x返回不大于x

因此，如果我们输入负数，例如-3.5，我们将获得:

So if we enter a negative number, like -3.5 we obtain:

Prelude> truncate (-3.5)
-3
Prelude> floor (-3.5)
-4

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