在R中使用hist()函数获取百分比，而不是原始频率 [英] Use hist() function in R to get percentages as opposed to raw frequencies

问题描述

如何使用R中的hist()函数绘制相对于原始频率的百分比?

How can one plot the percentages as opposed to raw frequencies using the hist() function in R?

推荐答案

仅使用freq=FALSE参数不能给出带有百分比的直方图，它可以对直方图进行归一化，因此总面积等于1.
要获取某些数据集的百分比直方图，例如x，请执行以下操作:

Simply using the freq=FALSE argument does not give a histogram with percentages, it normalizes the histogram so the total area equals 1.
To get a histogram of percentages of some data set, say x, do:

h = hist(x) # or hist(x,plot=FALSE) to avoid the plot of the histogram
h$density = h$counts/sum(h$counts)*100
plot(h,freq=FALSE)

基本上，您正在做的是创建一个直方图对象，将density属性更改为百分比，然后重新绘图.

Basically what you are doing is creating a histogram object, changing the density property to be percentages, and then re-plotting.

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