如何删除两个单词之间的字符串 [英] How to remove string between two words

问题描述

我正在使用以下代码行下载网页，

I am downloading web pages using below lines of code,

WebRequest request = WebRequest.Create(strURL);
WebResponse response = request.GetResponse();
Stream data = response.GetResponseStream();

string html = String.Empty;
using (StreamReader sr = new StreamReader(data))
{
  html = sr.ReadToEnd();
}

然后从这里提取身体部位，如下所示:

then from here I am extracting body part as below:

int nBodyStart = downloadString.IndexOf("<body");
int nBodyEnd = downloadString.LastIndexOf("</body>");
String strBody = downloadString.Substring(nBodyStart, (nBodyEnd - nBodyStart + 7));

现在我要删除正文部分附带的所有javascript，我该怎么做?

Now I want to remove any javascript attached in the body part, How can I do that?

我的目标是获取网页的唯一内容.但是由于每个页面的处理方式可能不同，所以我尝试删除所有js标签，然后使用下面的RegEx删除所有HTML标签

My aim to get the only contents of the web page. But as each page may have different approach, so I am trying to remove any js tags and then remove any HTML tags using below RegEx

Regex.Replace(strBody, @"<[^>]+>|&nbsp;", "").Trim();

但是我不知道如何删除脚本标记之间的js，因为脚本可能是多行或单行.

But I don't know how to remove js between script tags as the script may be multi-line or single line.

谢谢.

推荐答案

要匹配脚本标签(包括标签对的内部)，请使用以下命令:

To match script tags (including the inside of the pair), use the following:

<script[^>]*>(.*?)</script>

要匹配所有HTML标记(但不能匹配该对的内部标记)，您可以使用:

To match all HTML tags (but not the inside of the pair) you can use:

</?[a-z][a-z0-9]*[^<>]*>

我刚刚意识到您可能也想删除样式标签:

I just realised you might also want to remove style tags too:

<style[^>]*>(.*?)</style>

完整的正则表达式字符串在这里:

Full regular expression string here:

<script[^>]*>(.*?)</script>|<style[^>]*>(.*?)</style>|</?[a-z][a-z0-9]*[^<>]*>|<[^>]+>|&nbsp;

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