使用Python中的可点击内容来抓取网站 [英] Scraping a website with clickable content in Python
问题描述
我想在以下网站上抓取内容:
I would like to scrap the content a the following website:
http://financials.morningstar.com/ratios/r.html? t = AMD
在其中 Key Ratios 下,我想单击"Growth"按钮,然后在Python中抓取数据.
In there under Key Ratios I would like to click on "Growth" button and then scrap the data in Python.
我该怎么做?
推荐答案
您可以使用requests
+ BeautifulSoup
来解决.发送到 http://financials.morningstar.com/financials/的异步GET
请求您需要模拟的getKeyStatPart.html 端点. Growth
表位于div
中,且带有id="tab-growth"
:
You can solve it with requests
+BeautifulSoup
. There is an asynchronous GET
request sent to the http://financials.morningstar.com/financials/getKeyStatPart.html endpoint which you need to simulate. The Growth
table is located inside the div
with id="tab-growth"
:
from bs4 import BeautifulSoup
import requests
url = 'http://financials.morningstar.com/ratios/r.html?t=AMD'
keystat_url = 'http://financials.morningstar.com/financials/getKeyStatPart.html'
with requests.Session() as session:
session.headers = {'User-Agent': 'Mozilla/5.0 (Linux; U; Android 4.0.3; ko-kr; LG-L160L Build/IML74K) AppleWebkit/534.30 (KHTML, like Gecko) Version/4.0 Mobile Safari/534.30'}
# visit the target url
session.get(url)
params = {
'callback': '',
't': 'XNAS:AMD',
'region': 'usa',
'culture': 'en-US',
'cur': '',
'order': 'asc',
'_': '1426047023943'
}
response = session.get(keystat_url, params=params)
# get the HTML part from the JSON response
soup = BeautifulSoup(response.json()['componentData'])
# grab the data
for row in soup.select('div#tab-growth table tr'):
print row.text
这篇关于使用Python中的可点击内容来抓取网站的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!