如何使HTTPServer和BasicHTTPRequestHandler的stderr输出静默/安静? [英] How to silent/quiet HTTPServer and BasicHTTPRequestHandler's stderr output?
问题描述
作为我的项目的一部分，我正在编写一个简单的http服务器.以下是我的脚本的框架:
I am writing a simple http server as part of my project. Below is a skeleton of my script:
from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler
class MyHanlder(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.send_header('Content-type', 'text/html')
self.end_headers()
self.wfile.write('<html><body><p>OK</p></body></html>')
httpd = HTTPServer(('', 8001), MyHanlder)
httpd.serve_forever()
我的问题:每当客户端连接到服务器时，如何抑制脚本生成的stderr日志输出?
My question: how do I suppress the stderr log output my script produces every time a client connects to my server?
我已经查看了HTTPServer类，直到其父类为止，但是无法找到任何标志或函数调用来实现此目的.我还查看了BaseHTTPRequestHandler类，但找不到线索.我相信一定有办法.如果这样做，请与我和其他人分享；感谢您的努力.
I have looked at the HTTPServer class up to its parent, but was unable to find any flag or function call to achieve this. I also looked at the BaseHTTPRequestHandler class, but could not find a clue. I am sure there must be a way. If you do, please share with me and others; I appreciate your effort.
推荐答案
这可能会做到:
from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler
class MyHandler(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.send_header('Content-type', 'text/html')
self.end_headers()
self.wfile.write('<html><body><p>OK</p></body></html>')
def log_message(self, format, *args):
return
httpd = HTTPServer(('', 8001), MyHandler)
httpd.serve_forever()
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