大于小于，python [英] Greater than less than, python

问题描述

我正在做排名类型的事情，发生的事是我将分数与当前分数进行比较，如果分数低于当前分数，则玩家获得了较高的分数，但是在此处使用此代码

I am doing a ranking type thing, what happens is I compare the score to the current score and if the score is lower then the current then the player has got a high score, but when using this code here

        print "Score = " + str(score) + ", Compared to = " + str(array[x])
        if score < array[x]:
                #Do stuff here

但是，即使分数是4且array [x]是2，if语句仍然完成吗?

But even if score is 4 and array[x] is 2 the if statement is still done?

我做错什么了吗?

我的理解是，如果分数4和array [x]为2，那么4大于2，这意味着它返回False?

My understanding is that if score 4 and array[x] is 2 then 4 is greater than 2 which means it comes back False?

显示完整代码

def getRank(array, score):
    rank = 0
    rankSet = False
    for x in range(0, len(array)):
        print "Score = " + str(score) + ", Compared to = " + str(array[x])
        if score < array[x]:
            if not rankSet:
                rank = x
                print "Set rank to: " + str(rank)
                rankSet = True
        elif score == array[x] or score > array[x]:
            rank += 1
            print "Rank higher than " + str(x)
    print "Rank = " + str(rank)
    return rank

如果得分= 4并且数组由[1，2]组成，则会打印此内容

it prints this if score = 4 and the array is made up of [1, 2]

Score = 4, Compared to = 1
Set rank to: 0
Score = 4, Compared to = 2
Rank = 0

推荐答案

检查以确保score和array [x]均为数字类型.您可能正在将整数与字符串进行比较...这在Python 2.x中是令人心碎的.

Check to make sure that both score and array[x] are numerical types. You might be comparing an integer to a string...which is heartbreakingly possible in Python 2.x.

>>> 2 < "2"
True
>>> 2 > "2"
False
>>> 2 == "2"
False

编辑

进一步的解释: Python如何比较字符串和整数?

这篇关于大于小于，python的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！