Java7的条件语句 [英] Conditional Statement on Java7

问题描述

您好，我刚刚开始对hackerrank进行编码练习，并且使用带有skip功能的扫描器类遇到了一些挑战.这是我尝试过的. 客观的 在这个挑战中，我们从条件语句开始.查看教程"选项卡以获取学习材料和教学视频！

Hello i just started a coding exercise on hackerrank and i am having a little challenge using scanner class with the skip function. here is what i have tried. Objective In this challenge, we're getting started with conditional statements. Check out the Tutorial tab for learning materials and an instructional video!

任务

给出一个整数，执行以下条件操作:

• 如果n为奇数，则打印怪异
• 如果n为偶数且在2到5的范围内，则打印Not Weird
• 如果n为偶数且在6到20的范围内，则打印怪异
• 如果n为偶数且大于20，则打印Not Weird
• 完成编辑器中提供的存根代码以打印是否或 不是n很奇怪.

• If n is odd, print Weird
• If n is even and in the inclusive range of 2 to 5, print Not Weird
• If n is even and in the inclusive range of 6 to 20, print Weird
• If n is even and greater than 20, print Not Weird
• Complete the stub code provided in your editor to print whether or not n is weird.

输入格式

包含正整数n的单行.

A single line containing a positive integer,n.

约束

输出格式

如果数字很奇怪，请打印Weird；否则，请打印Not Weird.

Print Weird if the number is weird; otherwise, print Not Weird.

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;

public class Solution {


    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {
        int N = scanner.nextInt();

        if (N % 2 == 0 && N >= 2 && N <= 5 && N > 20) {
            System.out.println("not weird");

        } else if (N % 2 == 0 && N >= 6 && N <= 20) {
            System.out.println("weird");
        } else {
            System.out.println("weird");
        }

        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");


        scanner.close();
    }
}

请问我在做错什么.

推荐答案

您正在混合&&和||，因此您的第一个if将永远不会像注释中所述运行.

You're mixing up && and ||, so your first if will never run as mentioned in the comments.

因此，看起来唯一的"Not Weird"打印输出是2，4和偶数> 20.

So it looks like the only "Not Weird" print out is 2, 4 and even numbers > 20.

因此，您可以利用它来检查"Weird"输出，否则打印"Not Weird".

So use this to your advantage to just check for the "Weird" outputs, otherwise print "Not Weird".

if (n % 2 == 0) {
    if ((n >= 2 && n <= 5) || (n > 20)) {
        return "Not Weird";
    }
}
return "Weird";

在线演示

Online Demo

话虽如此，我不确定

Having said this, I'm not sure what you want with Scanner::skip

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