从文本文件读取到结构向量,但文本文件行的长度不同 [英] reading from text file to struct vector, but text file lines are of different length
问题描述
我正在尝试从学生的文本文件中读取内容,并将每一行分配给struct数据成员.
I am trying to read from a text file of students and assign each line to a struct data member.
文本文件结构如下:
Name,Student code, Ability,Consistency,Program name:Subject list
文件中有两名学生:
Average Ant,204932,50,5,Short course:1
Brilliant Bison,234543,80,3,Bachelor of Bounciness:2,5,3
除了最后一部分(主题列表),学生之间的长度不同,我可以毫无问题地阅读所有信息. 我该如何编写代码,以便如果一个学生只有1个像平均蚂蚁这样的科目,我可以将其推入subjectList向量,但是如果他们有3个像出色的野牛一样,我仍然可以毫无问题地将它们全部推入?
I can read all of the information to a struct no problem except for the last part(subject list),that are of varying length between students. How can I write code so that if a student only has 1 subject like average ant I can push it into the subjectList vector but if they have 3 like brilliant bison I can still push them all in no problem?
我的代码:
struct Student
{
string name;
int code;
int ability;
int consistency;
string programName;
vector<int> subjectList;
};
void createStudents(string fileName)
{
string tempSubjectId;
int subjectId;
//temp variable to then use to convert them to int.
string codeTemp, abilityTemp, consistencyTemp;
std::ifstream studentFile(fileName);
//A new student data member is created
Student newStudent;
if(studentFile.is_open() && studentFile.good())
{
cout << " " << endl;
cout << "---Reading from Students---" << endl;
while(getline(studentFile,newStudent.name, ','))
{
//we go get each value which is delimited by a comma and one by a colon
//getline(studentFile, newStudent.name, ',');
//To convert the strings to an int, the string is given to a temporary variable
//Then the temporary variable is parsed to an int using stoi and the code datamember from the struct is assign to that new int
getline(studentFile, codeTemp, ',');
newStudent.code = stoi(codeTemp);
getline(studentFile, abilityTemp, ',');
newStudent.ability = stoi(abilityTemp);
getline(studentFile, consistencyTemp, ',');
newStudent.consistency = stoi(consistencyTemp);
getline(studentFile, newStudent.programName, ':');
//want to push ints into subject list here.
//The new struct data member is added to the vector and returned for further use.
studentList.push_back(newStudent);
}
//file is then closed
studentFile.close();```
推荐答案
在主循环中,将整行读取为std::string
,然后使用std::istringstream
解析每一行,并使用内部循环读取主题整数,例如:
In your main loop, read an entire line into a std::string
, then use a std::istringstream
to parse each line, using an inner loop to read the subject ints, eg :
#include <string>
#include <sstream>
#include <fstream>
#include <vector>
struct Student
{
std::string name;
int code;
int ability;
int consistency;
std::string programName;
std::vector<int> subjectList;
};
std::vector<Student> studentList;
void createStudents(std::string fileName)
{
std::string tempLine;
//temp variable to then use to convert them to int.
std::string tempStr;
std::ifstream studentFile(fileName);
if (studentFile.is_open())
{
std::cout << " " << std::endl;
std::cout << "---Reading from Students---" << std::endl;
while (std::getline(studentFile, tempLine))
{
std::istringstream iss(tempLine);
//A new student data member is created
Student newStudent;
//we go get each value which is delimited by a comma and one by a colon
std::getline(iss, newStudent.name, ',');
//To convert the strings to an int, the string is given to a temporary variable
//Then the temporary variable is parsed to an int using stoi and the code datamember from the struct is assign to that new int
std::getline(iss, tempStr, ',');
newStudent.code = std::stoi(tempStr);
std::getline(iss, tempStr, ',');
newStudent.ability = std::stoi(tempStr);
std::getline(iss, tempStr, ',');
newStudent.consistency = std::stoi(tempStr);
std::getline(iss, newStudent.programName, ':');
// push ints into subject list
while (std::getline(iss, tempStr, ',')) {
newStudent.subjectList.push_back(std::stoi(tempStr));
}
//The new struct data member is added to the vector and returned for further use.
studentList.push_back(std::move(newStudent));
}
//file is then closed
studentFile.close();
}
}
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