根据属性值从ImmutableJS列表中删除对象 [英] Delete object from ImmutableJS List based upon property value

问题描述

基于属性值从列表中删除对象的最简单方法是什么?

What would be the simplest way to delete an object from a List based on a value of a property?

我正在寻找与MongoDB中的$ pull等效的东西.

I'm looking for an equivalent of the $pull in MongoDB.

我的列表看起来很简单:

My List looks simple like this:

[{a: '1' , b: '1'},{a: '2' , b: '2'}]

我想从数组中删除属性 a 设置为"1"的对象.在MongoDB中，我会这样:

And I'd like to remove from the array the object with property a set to '1'. In MongoDB, I'd do it like this:

Model.update({_id: getCorrectParentObj},{ $pull: {listIDeleteFrom: { a: '1' } } },(err, result)=>{});

如何使用ImmutableJS获得相同的结果?

How can I get the same result with ImmutableJS?

推荐答案

您可以简单地

You could simply filter the immutable list:

var test = Immutable.List.of(Immutable.Map({a: '1'}), Immutable.Map({a: '2'}));
test = test.filter(function(item) { return item.get('a') !== '1' });

但是，非空List上的filter会导致不同的不可变列表，因此您可能要首先检查{a: 1}的出现:

However, filter on non-empty List would result a different immutable list, thus you may want to check the occurrence of {a: 1} first:

if (test.some(function(item) { return item.get('a') === '1'; })) {
    test = test.filter(function(item) { return item.get('a') !== '1' });
}

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