sed增量编号 [英] sed increment number

问题描述

我想用增量值替换一些文本. 考虑文件xx:

I'd like to substitute some text with an incremental value. Considering file xx:

<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>

和sed命令:

for n in seq 3;do sed -e 's/<RecordID>\d/<RecordID>'`echo $n`'/' xx; done

echo $n命令不会递增.

也尝试过

n=1; sed -e 's/<RecordID>/<RecordID>'`echo $n ;let n=$n+1`'/g' xx

但没有成功.

仅考虑sed(没有awk或perl)，如何使RecordID字段增加，如:

Considering only sed (no awk or perl) how can I have the RecordID field incremented as in:

<outro>dfdfd</outro>
<RecordID>1</RecordID>
<outro>dfdfd</outro>
<RecordID>2</RecordID>
<outro>dfdfd</outro>
<RecordID>3</RecordID>
<outro>dfdfd</outro>

推荐答案

while read line; do n=$((++n)) &&  echo $line|sed -e 's/[0-9]/'$(($n))'/' ; done < patt

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