蚂蚁：转换为路径相对路径的逗号分隔的列表 [英] Ant: Convert comma-delimited list of relative paths to path

问题描述

我有一个逗号分隔的目录列表：

I have a comma-delimited list of directories:

foo,bar,baz,qux

我想将它转化为含有（像）以下的Ant路径：

I want to convert it to an Ant path containing (something like) the following:

${basedir}/build/foo/classes
${basedir}/build/bar/classes
${basedir}/build/baz/classes
${basedir}/build/qux/classes

好像应该有一种用＆LT做到这一点; pathconvert＆GT; ，但它并不明显，我会是怎样。建议？

It seems like there should be a way to do this with <pathconvert>, but it's not obvious to me what it would be. Suggestions?

推荐答案

您可能能够使用的 dirset 握住你的目录列表，然后反馈到这pathconvert。是这样的：

You might be able to use a dirset to hold your list of directories, then feed that into pathconvert. Something like:

<property name="dirs" value="foo,bar,baz,qux" />
<dirset id="dir_list" dir="${basedir}" includes="${dirs}" />

<pathconvert refid="dir_list" property="dirs_prop">
    <regexpmapper from="(${basedir})/(.*)" to="\1/build/\2/classes" />
</pathconvert>

则属性 $ {dirs_prop} 将持有你想...或几乎路径。与 dirset 的问题是，目录顺序没有定义。要保留原始列表的顺序，使用 文件清单： 到位的 dirlist ：

Then the property ${dirs_prop} will hold the path you want... or almost. The problem with dirset is that the order of directories is not defined. To retain the order of the original list, use a filelist in place of the dirlist:

<filelist id="dir_list" dir="${basedir}" files="${dirs}" />

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