为什么这段代码是无限循环的? [英] Why is this code an infinite loop?

问题描述

在完成此代码之前，我只是错误地对其进行了测试，并意识到它不会停止:

Before completing this code, I just tested it by mistake and realized that it will not stop:

$var = "any"; 
for ($i=1; $i < 2; $i++){ 
    $var.$i = "any"; 
}

为什么会产生无限循环?为什么PHP不会产生错误?

Why does this produce an infinite loop? And why doesn't PHP produce an error?

推荐答案

我做了一个简单的测试:

I did a simple test :

echo $i;
 $var.$i = "any";
var_dump($var);

结果:

1string(3) "any"
anzstring(3) "any"

因此$ i被转换为"anz"，并且没有通过验证就退出了循环.

So $i get transformed to "anz" and doesn't pass the validation to get out of the loop.

$ var.$ i =任何";是不是真的不对，我不知道您要做什么，但是如果您想填充和排列数组，则应该做更多类似的事情:

$var.$i = "any"; is not really correct, i don't know what you are trying to do, but if you want to fill and array you should do something more like :

$var = array();
for ($i=1; $i < 2; $i++){ 
 $var[] = "any";
}

如果要逐字母更改字符串:

If you want to change your string letter by letter :

$var = "any";
    for ($i=1; $i < 2; $i++){ 
     $var[$i] = "a"; // asign a new letter to the string at the $i position
    }

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