为什么我会收到“未引用的局部变量"?警告? (C ++) [英] Why do I get an "Unreferenced Local Variable" warning? (C++)

问题描述

当我做类似的事情

#include<iostream>
int main()
{
    int x;
    return 0;
}

我收到有关x是未引用的局部变量的警告(我假设是因为我创建了一个变量，然后未使用它)，为什么这会给我警告?

I get a warning about x being an unreferenced local variable (I assume becuase I created a variable, then did not use it), why does this give me a warning though?

推荐答案

可能是因为您无所事事地浪费了内存.

Probably because you're wasting memory for nothing.

此外，代码变得肮脏且难以理解，更不用说程序员通常不会定义他们不需要的变量，所以这有点像这真的是您的意思吗?"警告.

Besides, the code becomes dirty and harder to understand, not to mention that programmers don't usually define variables they don't need, so it's sort of a "is this really what you meant?" warning.

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