如何读取整数直到行尾? [英] How to read integers till end of line?
问题描述
鉴于邻接表,我正在尝试在图形上执行bfs. 这是示例输入.
I'm trying to do bfs on graph,given an adjacency list. Here's a sample input.
1 2 3
2 4
1
2 3 4
我知道行数n(顶点数). 每行包含0到n-1个整数.
I know the number of lines,n (number of verices). Each line contains 0 to n-1 integers.
这是一个尝试,但是它无法读取所有整数,直到输入结束.
This was an attempt but it doesnt work as it reads all the integers till the end of the input.
for(i=0;i<n;i++)
{
while(cin>>v)
{insert(i,v);}
}
我想分别处理每一行. 在搜索时,我发现了带有vector和stl的答案,如果有人可以提出一个更优雅的解决方案,那将是很好的.
I want to process each line separately. On searching, I found answers with vectors and stl.It would be nice if someone could come up with a more elegant solution.
谢谢.
推荐答案
首先,使用getline读取一行:
First, read a line with getline:
string line;
getline( cin, line ); // should be error handling here
然后,使用istringstream从行中读取整数:
Then, read the integers from the line using an istringstream:
istringstream is( line );
int n;
while( is >> n ) {
// do something with n
}
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