检查输入是否重复(Python) [英] Check for repetition in input (Python)

问题描述

我如何检查check子手游戏的重复输入(字母)?

How do i check for a repeating input(letter) for a hangman game?

示例:

单词是苹果

输入是猜字母:a

输出完成！

然后猜测下一个单词

输入是猜字母:a

输出应该是您已经猜到了那封信.

output should be you already guess that letter.

我的代码:

def checkValidGuess():
word = getHiddenWord()
lives = 10
num = ["1","2","3","4","5","6","7","8","9",]
#guessed = ''
while lives != 0 and word:
    print("\nYou have", lives,"guesses left")
    letter = input("Guess a letter or enter '0' to guess the word: ")
    if letter.lower() in word:
        print("Well done!", letter, "is in my word!")
        lives -= 1
    elif len(letter)>1:
        print("You can only guess one letter at a time!")
        print("Try again!")
    elif letter in num:
        print("You can only input letter a - z!")
        print("Try again!")
    #elif letter in guessed:
        #print("repeat")
    elif letter == "0":
        wword = input("What is the word?").lower()
        if wword == word:
            print("Well done! You got the word correct!")
            break
        else:
            print("Uh oh! That is not the word!")
            lives -= 1
    #elif letter == "":
        #print("Uh oh! the letter you entered is not in my word.")
        #print("Try again!")
    else:
        print("Uh oh! the letter you entered is not in my word.")
        print("Try again!")
        lives -= 1

谢谢.

推荐答案

这是一种简单的方法.首先初始化列表:

Here's an easy way. Start by initializing a list:

guesses = []

然后在循环中

letter = input("Guess a letter or enter '0' to guess the word: ")

if letter in guesses:
    print("Already guessed!")
    continue

guesses.append(letter)

这篇关于检查输入是否重复(Python)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！