接口Java1.8中的具体方法 [英] concrete methods in interfaces Java1.8
问题描述
在讨论中,我的一位朋友告诉我concrete methods would be allowed in java 1.8 in interfaces
,那时我想到一个问题,即如果允许,那么我们将如何区分这些方法.例如
我有两个接口Animal.java
和Pet.java
,并且都具有相同的具体方法,即eat()
During a discussion one of my friend tell me that concrete methods would be allowed in java 1.8 in interfaces
then at that time a question came into my mind i-e If they are allowed then How will we distinguish the methods.For example
I have two Interface Animal.java
and Pet.java
and both have same concrete method i-e eat()
public interfaces Animal{
void eat(){
System.out.println("Animal Start eating ....");
}
}
public interfaces Pet{
void eat(){
System.out.println("Pet Start eating ....");
}
}
现在,我的Zoo.java
都实现了这两个功能,并且没有覆盖
Now my Zoo.java
implement both of these and didn't override
public class Zoo() implements Pet , Animal{
//Now name method is a part of this class
}
现在这是我的困惑.如何使用Test
对象
Now here is my confusion.How can I call a specific method on inteface animal
using Test
object
public class Demo{
public static void main(String[] args){
Zoo zoo = new Zoo();
zoo.eat(); //What would be the output
}
}
有什么建议吗?还是在java1.8中对此有任何解决方案,因为我找不到答案?
Any suggestions? or is there any solution for this in java1.8 as I am unable to find its answer.
推荐答案
除非您在Zoo类中覆盖eat,否则您会收到编译时错误.
You get a compile time error, unless you override eat in your Zoo class.
java: class defaultMethods.Zoo inherits unrelated defaults for eat() from types Pet and Animal
最新,最漂亮的jdk是此处btw .语法应该是
The latest and geatest jdk is here btw. And the syntax should be
default void eat(){
System.out.println("Animal Start eating ....");
}
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