使用xcodebuild在模拟器上构建和运行应用 [英] Build and run an app on simulator using xcodebuild

问题描述

我要实现以下目标:使用xcodebuild和ios-sim生成并运行.app应用程序.

I have the following goal to achieve: build and run an .app application using xcodebuild and ios-sim.

我正在使用以下脚本来构建应用程序.

I'm using the following script to build the application.

xcrun xcodebuild \
  -scheme $XCODE_SCHEME \
  -project $XCODE_PROJECT \
  -configuration Debug \
  -destination generic/platform=iOS \
  -derivedDataPath \
  build

然后运行它，我正在使用

Then for running it, I'm using

ios-sim launch MyApp.app/ --devicetypeid "iPhone-6-Plus, 9.1"

每次我收到以下消息:

服务指定的程序不包含所请求的内容之一 体系结构:?

Program specified by service does not contain one of the requested architectures: ?

发生了什么事，该应用程序无法运行?

What is happening, that the app doesn't run?

注意:如果我针对从Xcode构建的.app(派生数据中包含的那个)运行第二个命令(ios-sim...)，则该程序运行正常.

Note: if I run the second command (ios-sim...) against the .app built from Xcode (the one contained in derived data) the procedure works fine.

推荐答案

好.找出问题所在.

您需要指定正确的destination.例如.

You need to specify the correct destination. For example.

xcrun xcodebuild \
  -scheme $XCODE_SCHEME \
  -project $XCODE_PROJECT \
  -configuration Debug \
  -destination 'platform=iOS Simulator,name=iPhone 6 Plus,OS=9.1' \
  -derivedDataPath \
  build

通过这种方式，Xcode将创建包含您的产品的文件夹(称为build)(特别是Debug-iphonesimulator). build目录是在您运行xcodebuild命令的目录中创建的.

In this way Xcode will create the folder (called build) containing your products (in particular look at Debug-iphonesimulator). The build dir is created within the dir you are running the xcodebuild command.

现在，您可以指向该文件夹以运行ios-sim命令(请参见 ios-sim 以获取更多参考)或simctl(请参见 iOS 8 :构建自定义模拟器和在Commmand Line中构建并运行iOS应用以获取更多信息).

Now you can point that folder in order to run the ios-sim command (see ios-sim for more references) or simctl (see iOS 8: Building custom simulators and Build And Run iOS Apps In Commmand Line for more info).

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