我正在计算文件中字符的数量，但我想计算少于5和6或更大的单词数 [英] im counting the number of characters in a file but i want to count the number of words that are less than 5 and 6 or greater

问题描述

我想这样做: 一次读取文件中的单词. (使用字符串执行此操作) 计算三件事:文件中有多少个单字符单词，文件中有多少个短字符(2至5个字符)，文件中有多少个长字符(6个或更多字符).在这里帮助

i want to do this: reads the words in the file one at a time. (Use a string to do this) Counts three things: how many single-character words are in the file, how many short (2 to 5 characters) words are in the file, and how many long (6 or more characters) words are in the file. HELP HERE

我不确定如何将文件读入字符串.我知道我必须要做类似的事情，但是我不理解其余的事情.在这里帮助

im not sure on how about reading file into a string. i know i have to something like this but i dont understand the rest. HELP HERE

ifstream infile;
//char mystring[6];
//char mystring[20];

 int main()
    {
        infile.open("file.txt");
            if(infile.fail())
            {
                cout << " Error " << endl;
            }

        int numb_char=0;
        char letter;

                while(!infile.eof())
                {
                    infile.get(letter);
                    cout << letter;
                    numb_char++;
                    break;
                }

    cout << " the number of characters is :" << numb_char << endl;
    infile.close(); 
    return 0;

推荐答案

我不太确定从哪里开始...

I'm not quite sure where to start...

您的循环:

while(!infile.eof())
{
  infile.get(letter);
  cout << letter;
  numb_char++;
  break;
}

由于额外的break;

此代码看起来也像是尝试读取文件中的字符数，而不是计算5个字母或大于6个字母的单词数.

Also this code looks like it is trying to read the number of characters in a file, and not count up the number of words that are 5 letters or greater than 6 letters.

尝试类似的东西:

ifstream infile;

int main(){
  infile.open("file.txt");
  if(!infile.good()){
    cout << " Error " << endl;
    return 1;
  }
  int shortCount = 0;
  int mediumCount = 0;
  int longCount = 0;
  int charCount = 0;
  char letter;
  while(!infile.eof()){
    infile >> letter;
    if(letter == ' ' || char == EOF){ // end of word or file.
      if(charCount == 1)
        shortCount++;
      else if(charCount < 6)
        mediumCount++;
      else
        longCount++;
      charCount = 0;
    }else{
      charCount++;
    }
  }
  cout << "Short Words: " << shortCount << endl;
  cout << "Medium Words: " << mediumWords << endl;
  cout << "Long Words: " << longWords << endl;
  infile.close();
  return 0;
}

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