从Python中的IP地址和掩码长度获取IP掩码 [英] Get IP Mask from IP Address and Mask Length in Python

问题描述

以点分四元符号给出IP地址，例如:
192.192.45.1
掩码长度通常为8、16、24，但可以是任何长度，即17.

Given an IP Address in dotted quad notation, for example:
192.192.45.1
And a mask length for example 8, 16, 24 typically, but could be anything i.e. 17.

有人可以提供python中的代码来计算子网掩码吗?最好我 可以将结果作为32位整数来获取，因此很容易进行哈希处理，然后在需要打印时将其重新解释为点分四边形.我看到python有一个套接字库，它基本上是unix套接字api的包装器.我还看到它具有函数inet_ntoa()， 但它返回某种数据包结构.我对Python struct库不是很熟悉，所以我希望其他人有一些想法.谢谢！

Can somebody please provide the code in python to calculate the subnet mask? Preferably I could get the result as 32-bit integer so that it is easy to hash and then reinterpret as dotted quad when necessary for printing. I see that python has a socket library which is basically a wrapper around the unix socket api. I also saw it has the function inet_ntoa(), but it returns some sort of packet struct. I'm not terribly familiar with the Python struct library, so I was hoping some other would have some ideas. Thanks!

推荐答案

最简单的方法是使用Google的 ipaddr 模块.我假设下面有一个25位的掩码，但是正如您所说的，它可以是任何东西

The simplest way is to use google's ipaddr module. I assume a 25 bit mask below, but as you say, it could be anything

>>> import ipaddr
>>> mask = ipaddr.IPv4Network('192.192.45.1/25')
>>> mask.netmask
IPv4Address('255.255.255.128')
>>>

该模块在处理IPv4和IPv6地址方面非常有效...其中一些其他功能的示例...

The module is rather efficient at manipulating IPv4 and IPv6 addresses... a sample of some other functionality in it...

>>> ## Subnet number?
>>> mask.network
IPv4Address('192.192.45.0')
>>>
>>> ## RFC 1918 space?
>>> mask.is_private
False
>>>
>>  ## The subnet broadcast address
>>> mask.broadcast
IPv4Address('192.192.45.127')
>>> mask.iterhosts()
<generator object iterhosts at 0xb72b3f2c>

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