在Jupyter Notebook中调试Flask服务器 [英] debug Flask server inside Jupyter Notebook
问题描述
我想在jupyter笔记本中调试小型烧瓶服务器以进行演示.
I want to debug small flask server inside jupyter notebook for demo.
我在最新的Ubuntu和Python2上创建了virtualenv(在使用Python3的Mac上也发生了此错误),pip安装flask jupyter.
I created virtualenv on latest Ubuntu and Python2 (on Mac with Python3 this error occurs as well), pip install flask jupyter.
但是,当我使用helloworld脚本创建单元时,它无法在笔记本中运行.
However, when I create a cell with helloworld script it does not run inside notebook.
from flask import Flask
app = Flask(__name__)
@app.route("/")
def hello():
return "Hello World!"
if __name__ == "__main__":
app.run(debug=True,port=1234)
文件 "/home/***/test/local/lib/python2.7/site-packages/ipykernel/kernelapp.py", 第177行,在_bind_socket中 s.bind("tcp://%s:%i"%(self.ip,端口))文件"zmq/backend/cython/socket.pyx",行495,在 zmq.backend.cython.socket.Socket.bind (zmq/backend/cython/socket.c:5653)文件 "zmq/backend/cython/checkrc.pxd",第25行,在 zmq.backend.cython.checkrc._check_rc (zmq/后端/cython/socket.c:10014) 引发ZMQError(errno)ZMQError:地址已在使用中
File "/home/***/test/local/lib/python2.7/site-packages/ipykernel/kernelapp.py", line 177, in _bind_socket s.bind("tcp://%s:%i" % (self.ip, port)) File "zmq/backend/cython/socket.pyx", line 495, in zmq.backend.cython.socket.Socket.bind (zmq/backend/cython/socket.c:5653) File "zmq/backend/cython/checkrc.pxd", line 25, in zmq.backend.cython.checkrc._check_rc (zmq/backend/cython/socket.c:10014) raise ZMQError(errno) ZMQError: Address already in use
NB-每次失败后,我都要更改端口号.
NB - I change the port number after each time it fails.
当然,它可以作为独立脚本运行.
Sure, it runs as a standalone script.
无需(debug = True)更新就可以.
update without (debug=True) it's ok.
推荐答案
我安装了Jupyter和Flask,您的原始代码也可以正常工作.
I installed Jupyter and Flask and your original code works.
flask.Flask
对象是WSGI应用程序,而不是服务器.当您在Shell中调用python -m flask run
时,Flask将Werkzeug的开发服务器用作WSGI
服务器.它创建一个新的WSGI服务器,然后将您的应用程序作为参数传递给werkzeug.serving.run_simple
.也许您可以尝试手动执行此操作:
The flask.Flask
object is a WSGI application, not a server. Flask uses Werkzeug's development server as a WSGI
server when you call python -m flask run
in your shell. It creates a new WSGI server and then passes your app as paremeter to werkzeug.serving.run_simple
. Maybe you can try doing that manually:
from werkzeug.wrappers import Request, Response
from flask import Flask
app = Flask(__name__)
@app.route("/")
def hello():
return "Hello World!"
if __name__ == '__main__':
from werkzeug.serving import run_simple
run_simple('localhost', 9000, app)
Flask.run()
在内部调用run_simple()
,因此此处应该没有区别.
Flask.run()
calls run_simple()
internally, so there should be no difference here.
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