使用正则表达式转换对话IRC日志? [英] Converting conversations IRC logs with regex?

问题描述

所以这里有来自BNC的IRC日志，格式为(其中[AA:BB:CC]不是实际时间，只有加载时间):

So here I have IRC logs which come from a BNC in the format of (where [AA:BB:CC] is not the actual time, only the time of loading):

[AA:BB:CC] <Person1> [re:al:ts] BLAH BLAH BLAH
[AA:BB:CC] <Person2> [an:ot:he] BLAH BLAH BLAH
[AA:BB:CC] <Person3> [rr:ea:lt] BLAH BLAH BLAH
[AA:BB:CC] <Person4> [im:es:tp] BLAH BLAH BLAH

我想将其转换为:

[re:al:ts] <Person1> BLAH BLAH BLAH
[an:ot:he] <Person2> BLAH BLAH BLAH
[rr:ea:lt] <Person3> BLAH BLAH BLAH
[im:es:tp] <Person4> BLAH BLAH BLAH

这在技术上可行吗?我看到[AA:BB:CC]可以轻松删除，但是我如何保留真实的时间戳并将其移至该行的/beginning/而不删除"blah blah blah"或"s"呢?老实说，我对regex并不十分了解.

Is this technically possible? I see that [AA:BB:CC] could easily be removed, but how would I retain the real timestamps and move them to the /beginning/ of the line without removing the "blah blah blah" or ""s? To be honest, I'm not really well-versed in regex...

谢谢:) 枫

推荐答案

要解决的示例:

perl -pe 's/^\[..:..:..](.*)(\[..:..:..]) (.*)/$2$1$3/' <<EOT
[AA:BB:CC] <Person1> [re:al:ts] BLAH BLAH BLAH
[AA:BB:CC] <Person2> [an:ot:he] BLAH BLAH BLAH
[AA:BB:CC] <Person3> [rr:ea:lt] BLAH BLAH BLAH
[AA:BB:CC] <Person4> [im:es:tp] BLAH BLAH BLAH
EOT

输出:

[re:al:ts] <Person1> BLAH BLAH BLAH
[an:ot:he] <Person2> BLAH BLAH BLAH
[rr:ea:lt] <Person3> BLAH BLAH BLAH
[im:es:tp] <Person4> BLAH BLAH BLAH

如果AA，BB，CC等是数字，则在perl正则表达式中使用\d\d代替...

If AA, BB, CC, ... are numbers, then use \d\d instead of .. in perl regex.

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