Jackson根据属性名称反序列化 [英] Jackson deserialize based on property name

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本文介绍了Jackson根据属性名称反序列化的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下两种类型的JSON对象:

I have the following two types of JSON objects:

{"foo": "String value"}

{"bar": "String value"}

它们两者都代表同一基础对象的特殊类型.我如何使用Jackson来反序列化它们?类型信息仅由键本身表示,而不由任何键的值表示(几乎所有示例都使用键的值来确定类型:

Both of them represent a specialized type of the same base object. How can I use Jackson for deserializing them ? The type information is only represented by the keys themselves and not the value for any key (almost all examples use the value of the key for determining the type : https://github.com/FasterXML/jackson-docs/wiki/JacksonPolymorphicDeserialization)

推荐答案

Jackson不提供

Jackson doesn't offer an out of the box solution for that, but it doesn't mean that you are out of luck.

假设您的类实现一个公共接口或扩展一个公共类,如下所示:

Assuming that your classes implement a common interface or extend a common class, as shown below:

public interface Animal {

}

public class Dog implements Animal {

   private String bark;
   
   // Default constructor, getters and setters
}

public class Cat implements Animal {

   private String meow;
   
   // Default constructor, getters and setters
}

您可以基于属性名称创建自定义解串器.它允许您定义一个 unique 属性,该属性将用于查找类以对以下内容执行反序列化:

You can create a custom deserializer based on the property name. It allows you to define a unique property that will be used to look up the class to perform the deserialization to:

public class PropertyBasedDeserializer<T> extends StdDeserializer<T> {

    private Map<String, Class<? extends T>> deserializationClasses;

    public PropertyBasedDeserializer(Class<T> baseClass) {
        super(baseClass);
        deserializationClasses = new HashMap<String, Class<? extends T>>();
    }

    public void register(String property, Class<? extends T> deserializationClass) {
        deserializationClasses.put(property, deserializationClass);
    }

    @Override
    public T deserialize(JsonParser p, DeserializationContext ctxt)
            throws IOException, JsonProcessingException {

        ObjectMapper mapper = (ObjectMapper) p.getCodec();
        JsonNode tree = mapper.readTree(p);
        
        Class<? extends T> deserializationClass = findDeserializationClass(tree);
        if (deserializationClass == null) {
            throw JsonMappingException.from(ctxt, 
               "No registered unique properties found for polymorphic deserialization");
        }

        return mapper.treeToValue(tree, deserializationClass);
    }
    
    private Class<? extends T> findDeserializationClass(JsonNode tree) {
        
        Iterator<Entry<String, JsonNode>> fields = tree.fields();
        Class<? extends T> deserializationClass = null;
        
        while (fields.hasNext()) {
            Entry<String, JsonNode> field = fields.next();
            String property = field.getKey();
            if (deserializationClasses.containsKey(property)) {
                deserializationClass = deserializationClasses.get(property);
                break;  
            }
        }
        
        return deserializationClass;
    }
}

然后实例化并配置反序列化器:

Then instantiate and configure the deserializer:

PropertyBasedDeserializer<Animal> deserializer = 
        new PropertyBasedDeserializer<>(Animal.class);

deserializer.register("bark", Dog.class); // If "bark" is present, then it's a Dog
deserializer.register("meow", Cat.class); // If "meow" is present, then it's a Cat

将其添加到模块中

SimpleModule module = new SimpleModule("custom-deserializers", Version.unknownVersion());
module.addDeserializer(Animal.class, deserializer);

注册模块并照常执行反序列化:

Register the module and perform the deserialization as usual:

ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(module);

String json = "[{\"bark\":\"bowwow\"}, {\"bark\":\"woofWoof\"}, {\"meow\":\"meeeOwww\"}]";
List<Animal> animals = mapper.readValue(json, new TypeReference<List<Animal>>() { });

这篇关于Jackson根据属性名称反序列化的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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