类型'()=>上不存在如何解决“呼叫"的方法.任何' [英] How to resolve 'calls' does not exist on type '() => any'

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问题描述

测试我的angular2应用.我尝试设置一个间谍,然后检查它被调用了多少次.我仍然不断收到此TS错误

Testing my angular2 app. I try and set a spy and then check how many times it has been called. I keep getting this TS error though

类型'()=> any'上不存在属性'calls'.

Property 'calls' does not exist on type '() => any'.

如何解决此错误?

How Do I resolve this error?

describe('ssh Service', () => {
    let ref:SshRefService;

    beforeEach(() => {
        TestBed.configureTestingModule({
            providers: [
                { provide: SshRefService, useClass: refClass },
            ]
        });

    });

    beforeEach(inject([SshRefService], (sshRef:SshRefService) => {
        ref = sshRef
        spyOn(ref, 'getClient').and.returnValue(true)
    }));

    it('should mock an observable', () => {
        //service.list() calls ref.getClient() internally
        expect(service.list('/share')).toEqual(Observable.of(mockFileList));

        expect(ref.getClient.calls.count()).toBe(1);


    });
}); 

推荐答案

看起来SshRefService当前定义了getClient() : any.结果,它正确地引发了此错误.之所以发生这种情况,是因为模拟过程用Spy替换了属性/方法,但是Typescript无法知道发生了什么.

It looks like SshRefService currently defines getClient() : any. As a result, it's correctly throwing this error. This is happening because the mocking process replaces the property/method with the Spy, but Typescript has no way of knowing that's taken place.

由于您监视了SshRefService.getClient,因此有两种方法可以测试它是否被调用:

Since you've spied on SshRefService.getClient , you have two ways to test whether it's been called:

spyOn返回一个jasmine.Spy对象,该对象直接公开calls属性.您可以将spyOn(ref, 'getClient').and.returnValue(true)的结果保存在示例对象上,然后像这样进行测试:

spyOn returns a jasmine.Spy object, which exposes the calls property directly. You can save the result of spyOn(ref, 'getClient').and.returnValue(true) on the example object, and then test that like so:

expect(getClientSpy.calls.count()).toEqual(1)

首选(可能):您可以在对象本身的方法上运行Expect,就像这样:

Preferred (probably): You can run expect on the method on the object itself, like so:

expect(ref.getClient).toHaveBeenCalledTimes(1)

这篇关于类型'()=>上不存在如何解决“呼叫"的方法.任何'的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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