JavaFX-每行迭代GridPane节点-每行读取GridPane的节点 [英] JavaFX - Iterate GridPane nodes per row - Read Nodes of GridPane per row

问题描述

我正在使用JavaFX 8创建应用程序. 我使用拖放功能动态更改网格窗格的内容. 我希望按行或按行/列对GridPane内容进行迭代. JavaFX允许通过指定行和列在GridPane中添加节点.

I am creating an application using JavaFX 8. I change the content of a grid pane dynamically using drag/drop. I wish to iterate GridPane contents per row or per row/col. JavaFX allows adding nodes in a GridPane by specifying the row and column.

gridPane.add(node, col, row);

我想通过指定行和列以相同的方式读取GridPane的节点.
我想要类似以下内容的源代码(以下代码不正确)，

I would like to read the nodes of a GridPane on the same way, by specifying the row and column.
I would like to have something similar to the below source (the below code is not correct),

for(int row = 0; row < gridPaneHeight; row++) {
    for(int col = 0; row < gridPaneWidth; col++) {
        Node node = gridPane.get(col, row);
    }
}

推荐答案

如何

int[][] gridPaneNodes = new int[gridPaneWidth][gridPaneHeight] ;
for (Node child : gridPane.getChildren()) {
    Integer column = GridPane.getColumnIndex(child);
    Integer row = GridPane.getRowIndex(child);
    if (column != null && row != null) {
        gridPaneNodes[column][row] = child ;
    }
}

(或者，当您将它们放置在哪个单元格中时，您只需跟踪它们放置在哪个单元格中即可...)

(or, you could just keep track of which were placed in which cell when you put them there...)

那你就可以做

for (int row = 0; row < gridPaneHeight; row++) {
    for(int col = 0; row < gridPaneWidth; col++) {
        Node node = gridPaneNodes[column][row] ;
    }
}

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