从文本文件中读取和查找字符串 [英] read and find string from text file

问题描述

我正在使用以下代码将文本文件内容加载到GUI:

I am loading text file contents to GUI using this code:

try {
    BufferedReader br = new BufferedReader(new FileReader ("text.txt"));
    String line;                
    while ((line = br.readLine()) != null) {
        if (line.contains("TITLE")) {
            jTextField2.setText(line.substring(11, 59));
        }            
    }
    in.close();        
} catch (Exception e) {
}

然后是text.txt文件的内容:

Then contents of text.txt file:

JOURNAL   journal name                                               A12340001
TITLE     Sound, mobility and landscapes of exhibition: radio-guided A12340002
          tours at the Science Museum                                A12340003
AUTHOR    authors name                                               A12340004

在jTextField2上，我得到以下一行:展览的声音，流动性和风景:无线电引导" . 问题是我不知道如何获取jTextField2下一行科学馆旅游"的字符串..

On jTextField2 I am getting this line: "Sound, mobility and landscapes of exhibition: radio-guided". The problem is I don't know how to get to jTextField2 the string of next line "tours at the Science Museum".

我想问一下如何在jTextField2上同时显示这条线，即展览的声音，流动性和景观:科学馆的无线电导览" ?

I would like to ask how can I get both line on jTextField2 i.e. "Sound, mobility and landscapes of exhibition: radio-guided tours at the Science Museum"?

在此先感谢您的帮助.

推荐答案

如果您使用的是Java 8，并假设各列具有固定数量的字符，则可能会这样:

If you are using Java 8 and assuming that the columns have a fixed number of characters, you could something like this:

public static void main(String args[]) throws IOException {
    Map<String, String> sections = new HashMap<>();
    List<String> content = (List<String>)Files.lines(Paths.get("files/input.txt")).collect(Collectors.toList());
    String lastKey = "";
    for(String s : content){
        String k = s.substring(0, 10).trim(); 
        String v = s.substring(10, s.length()-9).trim();
        if(k.equals(""))
            k=lastKey;
        sections.merge(k, v, String::concat);
        lastKey=k;
    }
    System.out.println(sections.get("TITLE"));
}

第一列是键.如果键不存在，则使用最后一个键. Map用于存储键和值.当键已经存在时，该值将通过串联与现有键合并.

The first column is the key. When the keys does not exist, the last key is used. A Map is used to store the keys and the values. When the key already exist, the value is merged with the existing one by concatenation.

此代码输出预期的字符串:Sound, mobility and landscapes of exhibition: radio-guidedtours at the Science Museum.

This code outputs the expected String: Sound, mobility and landscapes of exhibition: radio-guidedtours at the Science Museum.

编辑:对于Java 7

For Java 7

public static void main(String args[]) {
    Map<String, String> sections = new HashMap<>();
    String s = "", lastKey="";
    try (BufferedReader br = new BufferedReader(new FileReader("files/input.txt"))) {
        while ((s = br.readLine()) != null) {
            String k = s.substring(0, 10).trim();
            String v = s.substring(10, s.length() - 9).trim();
            if (k.equals(""))
                k = lastKey;
            if(sections.containsKey(k))
                v = sections.get(k) + v; 
            sections.put(k,v);
            lastKey = k;
        }
    } catch (IOException e) {
        System.err.println("The file could not be found or read");
    }

    System.out.println(sections.get("TITLE"));
}

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