Javascript比较字符串并得出结尾差异 [英] Javascript compare strings and get end difference

问题描述

我有两个字符串. 字符串-答:快速的棕色狐狸" 字符串B:那只敏捷的棕色狐狸跳过了那只懒狗."

I have two strings. String A: "The quick brown fox" String B: "The quick brown fox jumps over the lazy dog."

字符串B将始终包含字符串A的逐字记录.永远不会有快速的黑狐狸"或快速而快速的棕色狐狸".

String B will always contain string A verbatim. There will never be a "quick black fox" or a "quick and speedy brown fox".

如何获得差异跳过懒狗"的字符串C"?

How do a get a "String C" of the difference "jumps over the lazy dog."?

推荐答案

const A = "The quick brown fox"

const B = "The quick brown fox jumps over the lazy dog."

const diff = (diffMe, diffBy) => diffMe.split(diffBy).join('')

const C = diff(B, A)

console.log(C) // jumps over the lazy dog.

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