如何使用Java流获取具有相同最大值的所有对象? [英] How to get all objects having the same max value with Java streams?
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问题描述
我有一些得分高手.我想使用流和过滤器让所有共享最大积分的玩家.
I have players which have points. I want to get all the players who share the max amount of points using a stream and a filter.
public class Player {
private int points; // Getter omitted
}
我可以通过以下方法做到这一点:首先让得分最高的玩家,然后过滤所有具有相同数量的玩家.
I can do this by first getting the player with the most points, and the filtering all players that have the same amount.
Player topPlayer = players.stream().max(Comparator.comparing(Player::getPoints)).orElse(null);
players.stream().filter(p -> p.getPoints() == topPlayer.getPoints()).collect(Collectors.toList());
这可以用单个谓词/单行完成吗?
Can this be done with a single predicate / single line ?
推荐答案
您可以先收集到TreeMap
,仅获取最后一个条目(最大值为
You could collect to a TreeMap
first and only get the last entry (where the max is)
players.stream()
.collect(Collectors.groupingBy(
Player::getPoints,
TreeMap::new,
Collectors.toList()
))
.lastEntry()
.getValue();
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