如何基于特定值进行聚合并在给定对象列表的情况下创建嵌套地图? [英] How to aggregate based on certain value and create nested map given a list of objects?

问题描述

我有一个List<SingleDay>，其中SingleDay是:

class SingleDay{ 
      private Date date;
      private String County;

   // otherstuff
}

我想通过以下转换将其转换为Map<LocalDate, Map<String,SingleDay>>:

I would like to convert this into a Map<LocalDate, Map<String,SingleDay>> by the following transformation:

Key: 2020-05-27, Value: {'County1'=SingleDay [date=2020-05-27, County='County1'],
                         'County2'=SingleDay [date=2020-05-27, County='County2'], 
                         'County3'=SingleDay [date=2020-05-27, County='County3']
                        }
Key: 2020-05-28, Value: {'County4'=SingleDay [date=2020-05-28, County='County4'],
                         'County5'=SingleDay [date=2020-05-28, County='County5'], 
                         'County3'=SingleDay [date=2020-05-28, County='County3']
                        }

请注意，这是我之前提出的问题:

Note, this is a question that arose from my previous question : How do you use java stream api to convert list of objects into a nested map based on information stored inside object?

推荐答案

执行以下操作:

Map<LocalDate, Map<String, SingleDay>> result = list.stream()
            .collect(Collectors.groupingBy(SingleDay::getDate, Collectors.toMap(SingleDay::getCounty, e -> e)));

演示:

import java.time.LocalDate;
import java.util.List;
import java.util.Map;
import java.util.stream.Collectors;

class SingleDay {
    private LocalDate date;
    private String County;

    public SingleDay(LocalDate date, String county) {
        this.date = date;
        County = county;
    }
    public LocalDate getDate() {
        return date;
    }

    public String getCounty() {
        return County;
    }

    @Override
    public String toString() {
        return "SingleDay [date=" + date + ", County=" + County + "]";
    }
    // otherstuff
}

public class Main {
    public static void main(String[] args) {
        List<SingleDay> list = List.of(
                new SingleDay(LocalDate.now(), "X"), 
                new SingleDay(LocalDate.now(), "Y"),
                new SingleDay(LocalDate.now(), "Z"), 
                new SingleDay(LocalDate.now().plusDays(1), "A"),
                new SingleDay(LocalDate.now().plusDays(1), "B"), 
                new SingleDay(LocalDate.now().plusDays(1), "C"));

        Map<LocalDate, Map<String, SingleDay>> result = list.stream()
                .collect(Collectors.groupingBy(SingleDay::getDate, Collectors.toMap(SingleDay::getCounty, e -> e)));

        // Display
        result.forEach((k, v) -> System.out.println("Key: " + k + ", Value: " + v));
    }
}

输出:

Key: 2020-05-27, Value: {A=SingleDay [date=2020-05-27, County=A], B=SingleDay [date=2020-05-27, County=B], C=SingleDay [date=2020-05-27, County=C]}
Key: 2020-05-26, Value: {X=SingleDay [date=2020-05-26, County=X], Y=SingleDay [date=2020-05-26, County=Y], Z=SingleDay [date=2020-05-26, County=Z]}

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