具有通配符字段的Java 8 ISO 8601间隔语法 [英] Java 8 ISO 8601 Interval syntax with wildcard field(s)

问题描述

我需要解析类似于ISO 8601语法的时间间隔表达式，只允许对字段使用通配符；并将开始和结束存储到两个LocalDateTime对象中.然后，我的Interval将具有与第三个LocalDateTime或OffsetDateTime进行比较的API，以检查其是否在时间间隔之内或之外.

I need to parse a time interval expression similar to ISO 8601 syntax, only allowing wildcard for fields; and storing the start and end into two LocalDateTime objects. My Interval would then have APIs to compare to a third LocalDateTime or OffsetDateTime to check if it falls inside or outside of the interval.

例如:解析"****-**-**T00:00:00Z/****-**-**T11:55:00Z"时，开始和结束时刻的日期应该是开始执行程序的日期(忽略遇到第二天的问题).我如何解析这样的表达式?

E.g.: when parsing "****-**-**T00:00:00Z/****-**-**T11:55:00Z", the date of the start and end instant should be the day of the start program execution (ignoring running into the next day problem). How can I parse an expression like this?

为了清楚起见，如果我今天运行它，它应该等效于解析"2016-04-06T00:00:00Z/2016-04-06T11:55:00Z".

to make it clear, if I run it today, it should be equivalent of parsing "2016-04-06T00:00:00Z/2016-04-06T11:55:00Z".

推荐答案

我认为没有办法在使用java.time 解析字符串时使用通配符.一个不太好看的技巧是将*替换为1:这不应产生任何无法解析的日期.然后，您可以忽略日期内容.

I don't think there is a way to use wildcards when parsing a string with java.time. A not so good-looking hack would be to replace the * by 1: that should not produce any unparseable date. You can then ignore the date content.

例如:

String input = "****-**-01T00:00:00Z/****-04-**T11:55:00Z";
String[] dates = input.replace("*", "1").split("/");
ZonedDateTime zdt1 = ZonedDateTime.parse(dates[0]);
ZonedDateTime zdt2 = ZonedDateTime.parse(dates[1]);

LocalDate day = LocalDate.now(); //or whatever date you like

LocalDateTime start = zdt1.toLocalTime().atDate(day);
LocalDateTime end = zdt2.toLocalTime().atDate(day);

System.out.println(start + " / " + end);

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