JAXB-使用xsi:type进行封送 [英] JAXB - marshal with xsi:type

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本文介绍了JAXB-使用xsi:type进行封送的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我对使用jaxb进行编组有点陌生,我正在尝试从我的对象中创建此xml:

I'm kind of new to marshalling with jaxb and I'm trying to make this xml from my objects:

<Process_Bericht_Result xsi:type="Type_Proces_Bericht_Result_v2"
xmlns="http://www.centralbrokersystem.org"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>
   <Result_Data>
      ....
   </Result_Data>
</Process_Bericht_Result>

我得到的是以下内容:

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Proces_Bericht_result xmlns="http://www.centralbrokersystem.org">
    <Result_Data>
       ...
    </Result_Data>
</Proces_Bericht_result>

我想定义xsi:type ...

I would like to define the xsi:type...

我正在使用以下代码创建这些对象:

I'm creating these objects with the following code:

JAXBElement element = new JAXBElement(
            new QName("http://www.centralbrokersystem.org", "Proces_Bericht_Result"), TypeProcesBerichtResultV2.class, typeProcesBerichtResultV2);

我必须创建一个JAXBElement,因为TypeProcesBerichtResultV2类没有用@RootElement注释,并且它是用jaxB maven插件生成的,所以我不能更改它.

I have to create a JAXBElement because the TypeProcesBerichtResultV2 class isn't annotated with @RootElement and it's generated with the jaxB maven plugin so I can't change it.

然后我正在调用一个方法:

Then I'm calling a method:

XmlUtils.object2Xml(element, TypeProcesBerichtResultV2.class)

,该方法的实现是:

    public static String object2Xml(Object obj,
                                Class clazz)  {
    String marshalledObject = "";
    if (obj != null) {
        try {
            JAXBContext jc = JAXBContext.newInstance(clazz);
            Marshaller marshaller = jc.createMarshaller();
            marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT,
                    new Boolean(true));
            StringWriter sw = new StringWriter();

            marshaller.marshal(obj, sw);
            marshalledObject = new String(sw.getBuffer());
        } catch (Exception ex) {
            throw new RuntimeException("Unable to marshall the object", ex);
        }
    }
    return marshalledObject;
}

我应该更改为编组为正确的xml吗?

What should I change to marshal to the correct xml?

我要编组的元素是以下生成的对象:

The element that I'm trying to marshal is the following generated Object:

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "Type_Proces_Bericht_Result_v2", propOrder = {
"resultData",
"statusPartner"
})
public class TypeProcesBerichtResultV2
    extends TypeProcesBerichtResultBase
{

    @XmlElement(name = "Result_Data", required = true)
    protected TypeResultData resultData;

    ...

推荐答案

我已通过更改以下语句对其进行了修复:

I've fixed it with changing the following statements:

 JAXBElement element = new JAXBElement(
        new QName("http://www.centralbrokersystem.org", "Proces_Bericht_Result"), TypeProcesBerichtResultV2.class, typeProcesBerichtResultV2);

更改为:

JAXBElement element = new JAXBElement(
        new QName("http://www.centralbrokersystem.org", "Proces_Bericht_Result"), TypeProcesBerichtResultBase.class, typeProcesBerichtResultV2);

XmlUtils.object2Xml(element, TypeProcesBerichtResultV2.class)

更改为

XmlUtils.object2Xml(element, TypeProcesBerichtResultBase.class)

请注意,我现在如何将baseClass作为类型而不是实际的类进行编组.这会投放xsi:type标记.

Notice how I'm now marshalling with the baseClass as type instead of the actual class. This ads the xsi:type tag.

这篇关于JAXB-使用xsi:type进行封送的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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