如何重新启动启动我的应用程序特定类的Java应用程序? [英] How to restart a Java Application launching a specific class of my application?

问题描述

我的情况如下:

我有一个Java Swing 应用程序.

I have a Java Swing application.

在实现GUI的类中，我有一个名为注销的按钮，它绑定到处理click事件的事件侦听器，类似这样:

In the class that implement my GUI I have a button named Log Out tath is binding to an event listener that handle the click event, something like it:

JButton logOutButton = new JButton("LogOut");
header.add(logOutButton);

然后在实现我的GUI的同一类中，我声明了 ActionListener ，它使用内部类来处理此事件:

Then in the same class that implement my GUI I have declared the ActionListener that handle this event using an inner class:

    logOutButton.addActionListener(new ActionListener() {
        public void actionPerformed(ActionEvent event) {
            System.out.println("logOutButton clicked !!!");
            System.exit(0);
        }
    });

此刻，当我单击 logOutButton 按钮时，程序结束.我宁愿退出它，也可以通过运行一个名为 LoginForm 的特定类(实现登录表单GUI的类)来重新启动它

In this moment when I click the logOutButton button the program end. I would that instead exit it is restarted by running a specific class called LoginForm (the class that implement the login form GUI)

该怎么办?

Tnx

安德里亚

推荐答案

您根本不需要close/open window垃圾方法.只需使用卡片布局:

You don't really need to close/open window junky approach at all. Just use Card Layout:

1. 将框架的内容窗格的布局设置为卡片布局.

1. set Frame's content pane's layout to card layout.

getContentPane().setLayout(new CardLayout());

将您不同的Form的内容代码放入不同的面板中，然后 使用相应的名称将它们添加到内容窗格中，例如:

Put your different Form's content code inside different panel and add them to the content pane with their corresponding name, for example:

 getContetnPane().add(logInFormPanel, "logIn Form");

现在，您可以通过调用CardLayout.show(Container parent, String name)来模拟该卡在必要时显示.例如:

Now you can simulate the card to appear whenever necessary by calling CardLayout.show(Container parent, String name). For example:

 logOutButton.addActionListener(new ActionListener() {
         public void actionPerformed(ActionEvent event) {
              System.out.println("logOutButton clicked !!!");
          CardLayout cl = (CardLayout)(getContentPane().getLayout());
          cl.show(getContentPane(), "logIn Form");

    }
});

查看 CardLayout演示 从我的另一个答案中来.

Check out a CardLayout demo from my another answer.

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