接收消息，调用存储过程时无法找到对应的参数 [英] Receiving Message Unable to locate the Corresponding Parameter when calling Stored Procedure
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问题描述
我一直在阅读下面的Spring教程
I have been going through the following Spring Tutorial
http://www.tutorialspoint.com/spring/calling_stored_procedure.htm
一切正常，我唯一的问题是我收到以下消息.
Everything is working the only problem I have is that I am receiving the following message.
Apr 22, 2016 3:50:51 PM org.springframework.context.support.ClassPathXmlApplicationContext prepareRefresh
INFO: Refreshing org.springframework.context.support.ClassPathXmlApplicationContext@5910e440: startup date [Fri Apr 22 15:50:51 MDT 2016]; root of context hierarchy
Apr 22, 2016 3:50:51 PM org.springframework.beans.factory.xml.XmlBeanDefinitionReader loadBeanDefinitions
INFO: Loading XML bean definitions from class path resource [Beans.xml]
Apr 22, 2016 3:50:51 PM org.springframework.jdbc.datasource.DriverManagerDataSource setDriverClassName
INFO: Loaded JDBC driver: net.sourceforge.jtds.jdbc.Driver
----Listing Record with ID = 2 -----
Apr 22, 2016 3:50:52 PM org.springframework.jdbc.core.metadata.CallMetaDataContext matchInParameterValuesWithCallParameters
WARNING: Unable to locate the corresponding parameter value for 'outName' within the parameter values provided: [inID]
Apr 22, 2016 3:50:52 PM org.springframework.jdbc.core.metadata.CallMetaDataContext matchInParameterValuesWithCallParameters
WARNING: Unable to locate the corresponding parameter value for 'outAge' within the parameter values provided: [inID]
ID : 3, Name : Ayan, Age : 15
唯一的区别是我正在使用MSSQL.如您所见，结果返回.我什至传入了一个不同的参数，并且值发生了变化，所以我知道它正在工作.我只是不确定为什么我会收到这些消息.我已经验证了参数名称是否与该类中的参数匹配.
The only difference is I am using a MSSQL. As you can see the results return. I've even passed in a different parameter and the value changes so I know it's working. I'm just not sure why I am receiving these messages. I've verified that the parameters name match with what is in the class.
package com.tutorialspoint;
import java.util.List;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import com.tutorialspoint.StudentJDBCTemplate;
public class MainApp {
public static void main(String[] args) {
ApplicationContext context =
new ClassPathXmlApplicationContext("Beans.xml");
StudentJDBCTemplate studentJDBCTemplate =
(StudentJDBCTemplate)context.getBean("studentJDBCTemplate");
/*
System.out.println("------Records Creation--------" );
studentJDBCTemplate.create("Zara", 11);
studentJDBCTemplate.create("Nuha", 2);
studentJDBCTemplate.create("Ayan", 15);
System.out.println("------Listing Multiple Records--------" );
List<Student> students = studentJDBCTemplate.listStudents();
for (Student record : students) {
System.out.print("ID : " + record.getId() );
System.out.print(", Name : " + record.getName() );
System.out.println(", Age : " + record.getAge());
}
*/
System.out.println("----Listing Record with ID = 2 -----" );
Student student = studentJDBCTemplate.getStudent(3);
System.out.print("ID : " + student.getId() );
System.out.print(", Name : " + student.getName() );
System.out.println(", Age : " + student.getAge());
}
}
package com.tutorialspoint;
import java.sql.ResultSet;
import java.sql.SQLException;
import org.springframework.jdbc.core.RowMapper;
public class StudentMapper implements RowMapper<Student> {
public Student mapRow(ResultSet rs, int rowNum) throws SQLException {
Student student = new Student();
student.setId(rs.getInt("id"));
student.setName(rs.getString("name"));
student.setAge(rs.getInt("age"));
return student;
}
}
package com.tutorialspoint;
import java.util.Map;
import java.util.List;
import javax.sql.DataSource;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.namedparam.MapSqlParameterSource;
import org.springframework.jdbc.core.namedparam.SqlParameterSource;
import org.springframework.jdbc.core.simple.SimpleJdbcCall;
public class StudentJDBCTemplate implements StudentDAO {
private DataSource dataSource;
private SimpleJdbcCall jdbcCall;
public void setDataSource(DataSource dataSource){
this.dataSource = dataSource;
this.jdbcCall = new SimpleJdbcCall(dataSource).withProcedureName("getRecord");
}
public void create(String name, Integer age){
JdbcTemplate jdbcTemplateObject = new JdbcTemplate(dataSource);
String SQL = "INSERT INTO Student(name,age) VALUES (?,?)";
jdbcTemplateObject.update(SQL,name,age);
System.out.println("Created Record Name = " + name + " Age = " + age);
return;
}
public Student getStudent(Integer id){
SqlParameterSource in = new MapSqlParameterSource().addValue("inID", id);
Map<String, Object> out = jdbcCall.execute(in);
Student student = new Student();
student.setId(id);
student.setName((String) out.get("outName"));
student.setAge((Integer) out.get("outAge"));
return student;
}
public List<Student> listStudents(){
String SQL = "SELECT * FROM Student";
JdbcTemplate jdbcTemplateObject = new JdbcTemplate(dataSource);
List <Student> students = jdbcTemplateObject.query(SQL, new StudentMapper());
return students;
}
}
package com.tutorialspoint;
public class Student {
private Integer age;
private String name;
private Integer id;
public void setAge(Integer age) {
this.age = age;
}
public Integer getAge() {
return age;
}
public void setName(String name) {
this.name = name;
}
public String getName() {
return name;
}
public void setId(Integer id) {
this.id = id;
}
public Integer getId() {
return id;
}
}
推荐答案
它对我来说也添加了参数声明，但略有不同:
It worked for me adding the parameter declaration too, but slightly different:
public Student getStudent(Integer id) {
SqlParameterSource in = new MapSqlParameterSource().addValue("id", id, Types.INTEGER)
.addValue("name",Types.VARCHAR)
.addValue("age", Types.INTEGER);
Map<String, Object> out = jdbcCall.execute(in);
Student student = new Student();
student.setId(id);
student.setName((String) out.get("name"));
student.setAge((Integer) out.get("age"));
return student;
}
请注意，我使用的是MS SQL Server而不是MySQL；并且创建的过程略有不同:
please note i was using MS SQL Server instead of MySQL; and have created the procedure slightly different:
CREATE PROCEDURE getRecord
@id INT,
@name VARCHAR(20) OUTPUT ,
@age INT OUTPUT
AS
SELECT @name = name, @age = AGE
FROM Student where id = @id
但它应该非常相似.
这篇关于接收消息，调用存储过程时无法找到对应的参数的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
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