在CakePHP 3.0中的add方法中将其他数据保存到联接表中 [英] Saving Additional Data to the Join Table in the add method in CakePHP 3.0

问题描述

在这本书的示例中:

https://book.cakephp .org/3.0/en/orm/associations.html#using-the-through-option

class StudentsTable extends Table
{
    public function initialize(array $config)
    {
        $this->belongsToMany('Courses', [
            'through' => 'CoursesMemberships',
        ]);
    }
}

class CoursesTable extends Table
{
    public function initialize(array $config)
    {
        $this->belongsToMany('Students', [
            'through' => 'CoursesMemberships',
        ]);
    }
}

class CoursesMembershipsTable extends Table
{
    public function initialize(array $config)
    {
        $this->belongsTo('Students');
        $this->belongsTo('Courses');
    }
}

我想输入与课程#8相对应的grade，同时添加一个新的student.我遵循以下两个示例:

I want to enter grade corresponding to course #8 while adding a new student. I follow these two examples:

https://book.cakephp .org/3.0/en/orm/saving-data.html#saving-belongstomany-associations

和

https://book.cakephp .org/3.0/en/views/helpers/form.html#associated-form-inputs

并在StudentsController.php

public function add()
    {

        $student = $this->Students->newEntity();
        if ($this->request->is('post')) {
            $student = $this->Students->patchEntity($user, $this->request->getData(), [
    'associated' => [
                'Courses']]);


            if ($this->Students->save($student,['associated' => ['Courses._joinData']])) {
                $this->Flash->success(__('The student has been saved.'));

                return $this->redirect(['action' => 'index']);
            }
            $this->Flash->error(__('The student could not be saved. Please, try again.'));
        }
        $courses = $this->Students->Courses->find('list', ['limit' => 200]);
        $this->set(compact('student', 'courses'));
        $this->set('_serialize', ['student']);
    }

和Students/add.ctp要拥有

echo $this->Form->control('courses._ids', ['options' => $courses]);
echo $this->Form->control('courses.5._joinData.grade');

当我在视图中选择课程8并输入相应的成绩时，在CoursesMemberships表中看不到它.它会添加记录本身，但grade不存在.

When I select course #8 in the view and enter corresponding grade, I do not see it in CoursesMemberships table. It adds the record itself, but grade is not there.

推荐答案

您不能混合使用特殊的_ids语法和表示嵌套数据结构的传统语法，即property.index.field...(文档中有关该行为的注释不会受伤).

You cannot mix the special _ids syntax and the traditional syntax for expressing nested data structures, ie property.index.field... (a note in the docs regarding that behavior probably wouldn't hurt).

另外在索引5处添加数据似乎非常随意，您要添加新的链接/记录，因此通常从0开始.

Also adding data at index 5 seems very arbitrary, you're adding a new link/record, so you'd normally start at 0.

抛弃_ids语法，并通过显式定义其主键来构建适当的课程数据集，例如:

Ditch the _ids syntax and build a proper course dataset by explicitly defining its primary key, like:

echo $this->Form->control('courses.0.id', ['type' => 'select', 'options' => $courses]);
echo $this->Form->control('courses.0._joinData.grade');

另请参见

• 菜谱>视图>助手>表单>为关联数据创建输入

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