如何使用jq提取所有(也嵌套的)键名 [英] How to extract all (also nested) key names with jq

问题描述

即使在带有jq的嵌套对象中，如何提取所有键名? 例如，我有json:

How can I extract all key names, even in nested objects with jq? For example, I have json:

{ "a": 1, "b": { "c": 2 } }

{ "a": 1, "b": { "c": 2 } }

，我想获取列表: a，b，b.c

and I want to get list: a, b, b.c

我知道对于顶级密钥，我可以通过以下方式获得它: . | to_entries[] | .key，但是嵌套对象中的键呢?

I know that for top level keys I can get this, with: . | to_entries[] | .key, but what about keys in nested objects?

推荐答案

短 jq 解决方案:

jq -r '[paths | join(".")]'  jsonfile

输出:

[
  "a",
  "b",
  "b.c"
]

---

• paths函数将路径输入到其输入中的所有元素

  ---

  • paths function outputs the paths to all the elements in its input

    join(".")-在层级路径内串联键

    join(".") - to concatenate keys within hierarchical paths

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