jq递归更新某些元素的值 [英] jq recursively update values for certain elements

问题描述

以下JSON数据的目的是在type t的所有元素中使用src的值更新字段dst的值，而不管树中的深度如何，同时保留数据的整体结构.

The intent for the JSON data below is to update the value of the field dst with the value of src within all elements of type t, regardless of depth within the tree, while at the same time preserving the whole structure of the data.

使用jq可以吗?我的几次尝试都归结为以下无法实现预期目的的命令:

Is this possible with jq? My several attempts have boiled down to the following command that is not working to achieve the intended purpose:

$ jq -r 'map_values(select(.. | .type? == "t" |= (.dst = .src)))'

{
    "a": "b",
    "c": [
        {
            "type": "t",
            "src": "xx",
            "dst": "zz"
        },
        {
            "type": "t",
            "src": "xx",
            "dst": "zz"
        }
    ],
    "d": [
        {
            "e": [
                {
                    "type": "t",
                    "src": "xx",
                    "dst": "zz"
                }
            ]
        },
        {
            "type": "t2",
            "src": "xx",
            "dst": "zz"
        }
     ]
}

推荐答案

jq有可能吗?

Is this possible with jq?

jq是图灵完成的:-)

jq is Turing-complete :-)

这是一个简单的解决方案:

Here's a simple solution:

walk( if type == "object" and .type == "t" then .dst = .src else . end)

如果您的jq没有walk/1，则可能是升级(升级到jq 1.6)的好时机；否则，您可以从网络上获取其定义，例如通过谷歌搜索:jq "def walk"

If your jq does not have walk/1, then it might be a good time to upgrade (to jq 1.6); otherwise, you can snarf its def from the web, e.g. by googling: jq "def walk"

reduce paths as $x (.;
    if (getpath($x)|.type? // false) == "t"
    then setpath( $x + ["dst"]; getpath( $x + ["src"] ))
    else . end)

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