正则表达式的不平衡括号错误 [英] Unbalanced parenthesis error with Regex

问题描述

我正在使用以下正则表达式从以下字符模式中包含的网站Javascript数据源获取所有数据

I am using the following regex to obtain all data from a website Javascript data source that is contained within the following character pattern

[[]]);

我正在使用的代码是这样:

The code I am using is this:

regex = r'\[\[.*?\]]);'
        match2 = re.findall(regex, response.body, re.S)
        print match2

这引发了以下错误消息:

This is throwing up an error message of:

    raise error, v # invalid expression
sre_constants.error: unbalanced parenthesis

我认为这是由我的正则表达式内的右括号引起的，这是相当安全的.如何在不出现此错误的情况下定义所需的正则表达式?

I think I am fairly safe in assuming that this is being caused by the closing bracket within my regex. How can I define the regex that I want without getting this error?

谢谢

推荐答案

您还需要转义最后一个括号.字符类外部的方括号不必转义:

You need to escape those last parenthesis as well. Close square brackets outside a character class do not have to be escaped:

regex = r'\[\[.*?]]\);'
                   ^

如果您要获取方括号之间的内容，请在此处使用捕获组.

If you are trying to obtain the content between the square brackets, use a capturing group here.

>>> import re
>>> s = 'foo [[bar]]); baz [[quz]]); not [[foobar]]'
>>> matches = re.findall(r'\[\[(.*?)]]\);', s, re.S)
>>> matches
['bar', 'quz']

这篇关于正则表达式的不平衡括号错误的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！