用php删除json变量中的一些信息 [英] Delete some informations in a json variable with php

问题描述

我的问题是我正在解析XML文件，并且此文件包含一些我不想导出为JSON数据的信息.就我而言，我想要一个从第一个[[] caratere返回json数据的函数 这是php代码:

My problem is that i am parsing an XML file and this file contain some information that i don't want to exporting as JSON data. In my case i want a function that return the json data from the first '[' caratere this is the php code:

    <?php

class XmlToJsonConverter {
    public function ParseXML ($url) {
        $fileContents= file_get_contents($url);
        // Remove tabs, newline, whitespaces in the content array
        $fileContents = str_replace(array("\n", "\r", "\t"), '', $fileContents);
        $fileContents = trim(str_replace('"', "'", $fileContents));
        $myXml = simplexml_load_string($fileContents);
        $json = json_encode($myXml);
        return $json;
    }
}
//Path of the XML file
$url= 'http://www.lequipe.fr/rss/actu_rss_Football.xml';

//Create object of the class
$jsonObj = new XmlToJsonConverter();

//Pass the xml document to the class function
$myjson = $jsonObj->ParseXMl($url);
print_r ($myjson);
?>

这是JSON结果的一部分:

this is a part of the JSON result :

{"@ attributes":{"version":"2.0"}，"channel":{"title":"L'Equipe.fr Actu Football"，"link":"http://www.lequipe .fr"，描述":"L'Equipe.fr，足球足球"，语言":"fr"，版权":版权L'Equipe.fr"，"pubDate": 星期三，2015年4月22日16:31:08 +0200"，图片":{"url":"http://www.lequipe.fr/rss/logo_RSS.gif"，标题":"L'Equipe .fr，" link:" http://www.lequipe.fr，" width:" 119，" height:" 28}，" item:[{" title:" Foot-查

{"@attributes":{"version":"2.0"},"channel":{"title":"L'Equipe.fr Actu Football","link":"http://www.lequipe.fr","description":"L'Equipe.fr, Toute l'actualit\u00e9 du football","language":"fr","copyright":"Copyright L'Equipe.fr","pubDate":"Wed, 22 Apr 2015 16:31:08 +0200","image":{"url":"http://www.lequipe.fr/rss/logo_RSS.gif","title":"L'Equipe.fr","link":"http://www.lequipe.fr","width":"119","height":"28"},"item":[{"title":"Foot - Cha

我希望结果从"["

谢谢

推荐答案

在对json进行编码之前，删除不需要的每个属性:

Remove every attribute you don't want just before encoding json:

public function ParseXML ($url) {
    $fileContents= file_get_contents($url);
    // Remove tabs, newline, whitespaces in the content array
    $fileContents = str_replace(array("\n", "\r", "\t"), '', $fileContents);
    $fileContents = trim(str_replace('"', "'", $fileContents));
    $myXml = simplexml_load_string($fileContents);
    //--------------
    unset($myXml['@attributes']);
    unset($myXml['channel']);
    unset($myXml['image']);
    //--------------
    $json = json_encode($myXml);
    return $json;
}

或者如果您仅需要以下物品:

or if you only need the item:

public function ParseXML ($url) {
    $fileContents= file_get_contents($url);
    // Remove tabs, newline, whitespaces in the content array
    $fileContents = str_replace(array("\n", "\r", "\t"), '', $fileContents);
    $fileContents = trim(str_replace('"', "'", $fileContents));
    $myXml = simplexml_load_string($fileContents);
    //--------------
    $json = json_encode($myXml['item']);
    return $json;
}

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