从json模式动态创建mongoengine类 [英] creating mongoengine class dynamicly from json schema

问题描述

我正在寻找一种获取json模式并在运行时动态创建mongoengine类的方法.

i'm looking for a way to take my json schema and dynamically create a mongoengine class at runtime.

例如: 下面编写的mongoengine类

for example: the mongoengine class written below

class user(Document):
     _id  = StringField(required=False) # mongodb id
     name = StringField(required=True)  # user name
     email= StringField(required=False,regex="^[a-zA-Z0-9]*@mydomain.com$")  # user email

将与此模式下生成的在运行时动态生成的类相同

will be the same as the dynamically generated at runtime class generated from this schema

{
"type":"object",
"properties":{
    "_id"      : {"type":"string"},
    "name"     : {"type":"string"},
    "email"    : {"pattern":"^[a-zA-Z0-9]*@mydomain.com$"}
    }
}

有什么建议吗?

推荐答案

您可以动态创建python类，如下所示:

You can create python classes dynamically, like below:

user_properties = { 
   '_id': StringField(required=False), # mongodb id
   'name': StringField(required=True), # user name
   'email': StringField(required=False,regex="^[a-zA-Z0-9]*@mydomain.com$"),  # user email
}
User = type("User", (Document, ), user_properties)

其余的仅是来自具有您的模式"的字典的转换器.在输入中提供，将转换为字典user_properties .

The remaining is only convertor from dict with "your schema" provided on input, that will be converted to dict user_properties .

此外，这是对类似问题"我的答案 /a/63181047/3722635>如何从现有集合中为mongoengine文档生成模型"这也有帮助.

Also, here is my answer to similar question "How to generate a model for a mongoengine Document from an already existing collection" which can also help.

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