sequelize.query()返回两次相同的结果 [英] sequelize.query() returns same result twice

问题描述

我正在使用sequelize连接mysql数据库的nodejs项目中工作.我还使用 sequelize-values 从Sequelize实例获取原始数据.

I am working in nodejs project in that using sequelize for connecting mysql database. I am also using sequelize-values for getting raw data from Sequelize instances.

我写了下面的代码

var Sequelize = require('sequelize');
require('sequelize-values')(Sequelize);
var sequelizeObj = new Sequelize('mysql://root:@localhost/database');

sequelizeObj.authenticate().then(function (errors) {
    console.log(errors)
});

sequelizeObj.query("SELECT * FROM `reports` WHERE `id` = 1200").then(function (result) {

    });

现在表reports仅具有id 1200的1条记录，但是result为相同记录提供了两个对象，这意味着两个记录的ID均为1200.

Now the table reports have only 1 record for id 1200, But the result gives two objects for same records, Means both records are same of id 1200.

[ [ { id: 1200,
  productivity_id: 9969,
  gross_percentage_points: 100 } ],
[ { id: 1200,
  productivity_id: 9969,
  gross_percentage_points: 100 } ] ]

让我知道我在做什么错吗?

Let me know what I am doing wrong?

推荐答案

第一个对象是结果对象，第二个是元数据对象(包含受影响的行等)-但是在mysql中，这两个对象是相等的.

The first object is the result object, the second is the metadata object (containing affected rows etc) - but in mysql, those two are equal.

将{ type: Sequelize.QueryTypes.SELECT }作为第二个参数传递将给您一个结果对象(省略了元数据对象

Passing { type: Sequelize.QueryTypes.SELECT } as the second argument will give you a single result object (metadata object omitted

https://github.com/sequelize/sequelize/wiki/Upgradeing-to-2.0#changes-to-raw-query

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