使用TypeScript函数返回JSON对象 [英] Return JSON object with TypeScript function
问题描述
我最近发现了TypeScript,然后尝试将现有的JavaScript代码转换为TypeScript.
I discovered TypeScript recently and I try to convert my existing JavaScript code to TypeScript.
我有一个函数,可以从字符串(data
)中检索信息,将其放入JSON对象(json
)中并返回它.但是,当使用TypeScript而不指定返回类型时,在Eclipse中会出现以下错误:
I have a function that retrieves information from a string (data
), puts it in a JSON object (json
) and returns it. But when using TypeScript and not specifying a return type, I get the following error in Eclipse:
返回表达式之间不存在最佳通用类型
No best common type exists among return expressions
当我添加any
返回类型时,它消失了,但是我认为这不是一个很好的解决方案(太通用了).而且我找不到"json"或"object"类型.
It disappears when I add any
return type, but I think this isn't a good solution (too generic). And I couldn't find a "json" or "object" type.
我的问题是:我应该使用哪种退货类型?
My question is: what return type should I use?
这里是函数:
function formaterDonnees(data: string) { // or (data: string): any
// final json object
var json = {
y: {
"vars": [],
"smps": [],
"data": []
}
};
// ...
// processing data...
// ...
// put new variables in JSON (not real values below)
json.y.data = ["data"];
json.y.smps = ["smps"];
json.y.vars = ["vars"];
return json;
};
推荐答案
You can indeed specify that you return object
(new to typescript 2.2), but you can create a type for your return value:
type MyReturnTypeItem = {
vars: string[];
smps: string[];
data: string[];
}
type MyReturnType = {
[name: string]: MyReturnTypeItem;
}
function formaterDonnees(data: string): MyReturnType {
var json = {
y: {
"vars": [],
"smps": [],
"data": []
}
};
// put new variables in JSON (not real values below)
json.y.data = ["data"];
json.y.smps = ["smps"];
json.y.vars = ["vars"];
return json;
};
(操场上的代码)
Also, while I used type alias you can do the same with interfaces:
interface MyReturnTypeItem {
vars: string[];
smps: string[];
data: string[];
}
interface MyReturnType {
[name: string]: MyReturnTypeItem;
}
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