c ++ nlohmann json-如何迭代/查找嵌套对象 [英] c++ nlohmann json - how to iterate / find a nested object
问题描述
我正在尝试使用nlohmann :: json遍历嵌套的json.我的json对象如下:
I am trying to iterate over a nested json, using nlohmann::json. My json object is below:
{
"one": 1,
"two": 2
"three": {
"three.one": 3.1
},
}
我正在尝试迭代和/或查找嵌套对象.但是,似乎没有默认支持.看来我必须通过创建另一个循环来遍历每个子对象,或者为每个子对象递归调用fn.
I am trying to iterate and /or find nested objects. But, it seems there is no default support for it. It looks like I have to iterate over each sub-object by creating another loop, or call the fn recursively for every sub-object.
我下面的代码及其结果表明,仅可能进行顶级迭代.
My following piece of code, and its result indicate, that only top level iteration possible.
void findNPrintKey (json src, const std::string& key) {
auto result = src.find(key);
if (result != src.end()) {
std::cout << "Entry found for : " << result.key() << std::endl;
} else {
std::cout << "Entry not found for : " << key << std::endl ;
}
}
void enumerate () {
json j = json::parse("{ \"one\" : 1 , \"two\" : 2, \"three\" : { \"three.one\" : 3.1 } } ");
//std::cout << j.dump(4) << std::endl;
// Enumerate all keys (including sub-keys -- not working)
for (auto it=j.begin(); it!=j.end(); it++) {
std::cout << "key: " << it.key() << " : " << it.value() << std::endl;
}
// find a top-level key
findNPrintKey(j, "one");
// find a nested key
findNPrintKey(j, "three.one");
}
int main(int argc, char** argv) {
enumerate();
return 0;
}
和输出:
ravindrnathsMBP:utils ravindranath$ ./a.out
key: one : 1
key: three : {"three.one":3.1}
key: two : 2
Entry found for : one
Entry not found for : three.one
那么,是否有递归迭代可用,还是我们必须使用is_object()方法自己做?
So, is there a recursive iteration available, or do we have to do this ourselves, using is_object() method?
推荐答案
确实,迭代不会递归,并且还没有库函数.怎么样:
Indeed, iteration does not recurse and there is no library function for this (yet). What about:
#include "json.hpp"
#include <iostream>
using json = nlohmann::json;
template<class UnaryFunction>
void recursive_iterate(const json& j, UnaryFunction f)
{
for(auto it = j.begin(); it != j.end(); ++it)
{
if (it->is_structured())
{
recursive_iterate(*it, f);
}
else
{
f(it);
}
}
}
int main()
{
json j = {{"one", 1}, {"two", 2}, {"three", {"three.one", 3.1}}};
recursive_iterate(j, [](json::const_iterator it){
std::cout << *it << std::endl;
});
}
输出为:
1
"three.one"
3.1
2
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