在JSON模式中定义键值对的正确方法是什么 [英] What is the Correct way to define key-value pairs in json schema
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问题描述
如何在json模式中定义键值对对象(正确"的方式)?
How do i define key value pairs object in json schema (the "correct" way) ?
我想定义这个:
"id" : 99,
_info : {
"name" : "somename",
"href" : "someUrl"
}
以下两项是否正确?
1)
{
"type": "object",
"name": "MyObj",
"properties": {
"id": {
"type": "integer"
},
"_info": {
"type": "array",
"items": {
"type": "object"
"properties": {
"key": {
"type": "string",
"description": "key"
},
"value": {
"type": "string",
"description": "the value"
}
}
}
}
}
}
2)
{
"type": "object",
"name": "MyObj",
"properties": {
"id": {
"type": "integer",
"_info": {
"type": "object",
"additionalProperties": {
"type": "string",
"description": "string values"
}
}
}
}
实现此目标的正确方法是什么?人们会知道序列化/反序列化后的模式是什么,对象看起来像什么?
What is the correct way to get this accomplished and people will know what the schema is and the object will look like when serialized/deserialized?
推荐答案
在JSON中,对象已经是键值对的集合.您不需要任何特殊的定义即可:
In JSON an object is already a collection of key-value pairs. You don't need anything special in order to define it:
{
"_info":{"type":"object"}
}
您可以在此处添加约束.
From here you can add constraints.
- 如果您知道键的名称,则将它们添加到属性"中
- 如果您知道所有可能的键,请将"additionalProperties"设置为false
- 如果要限制可能的键名,请使用"patternProperties".
更新2019/09/10
如注释中所建议,如果要将所有属性限制为字符串类型,则可以通过以下方式做到这一点:
As suggested in comments, if you want to restrict all properties to be of type string, you may do it this way:
{
"title": "Force every property to have a string value",
"$schema": "http://json-schema.org/draft-07/schema#",
"type": "object",
"additionalProperties": {"type": "string"}
}
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